我用 spring data JPA 开发了一个 Spring boot 应用程序 有人有解决这个问题的方法吗?: 我的 bean :
@Entity
@Table(name = "employee", catalog = "explorerrh")
public class Employee implements java.io.Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
private Integer idemployee;
private String employeeName;
private String employeeLastName;
private String employeeCin;
private String employeePhone;
private String employeeAdress;
private String employeePost;
private String employeeCnss;
private String employeeCv;
private String employeePhoto;
private String employeeSalaire;
public Employee() {
}
public Employee(String employeeName, String employeeLastName,
String employeeCin, String employeePhone, String employeeAdress,
String employeePost, String employeeCnss, String employeeCv,
String employeePhoto, String employeeSalaire) {
this.employeeName = employeeName;
this.employeeLastName = employeeLastName;
this.employeeCin = employeeCin;
this.employeePhone = employeePhone;
this.employeeAdress = employeeAdress;
this.employeePost = employeePost;
this.employeeCnss = employeeCnss;
this.employeeCv = employeeCv;
this.employeePhoto = employeePhoto;
this.employeeSalaire = employeeSalaire;
}
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "idemployee", unique = true, nullable = false)
public Integer getIdemployee() {
return this.idemployee;
}
public void setIdemployee(Integer idemployee) {
this.idemployee = idemployee;
}
@Column(name = "employeeName", length = 45)
public String getEmployeeName() {
return this.employeeName;
}
public void setEmployeeName(String employeeName) {
this.employeeName = employeeName;
}
@Column(name = "employeeLastName", length = 45)
public String getEmployeeLastName() {
return this.employeeLastName;
}
public void setEmployeeLastName(String employeeLastName) {
this.employeeLastName = employeeLastName;
}
@Column(name = "employeeCIN", length = 45)
public String getEmployeeCin() {
return this.employeeCin;
}
public void setEmployeeCin(String employeeCin) {
this.employeeCin = employeeCin;
}
@Column(name = "employeePhone", length = 45)
public String getEmployeePhone() {
return this.employeePhone;
}
public void setEmployeePhone(String employeePhone) {
this.employeePhone = employeePhone;
}
@Column(name = "employeeAdress", length = 45)
public String getEmployeeAdress() {
return this.employeeAdress;
}
public void setEmployeeAdress(String employeeAdress) {
this.employeeAdress = employeeAdress;
}
@Column(name = "employeePost", length = 45)
public String getEmployeePost() {
return this.employeePost;
}
public void setEmployeePost(String employeePost) {
this.employeePost = employeePost;
}
@Column(name = "employeeCNSS", length = 45)
public String getEmployeeCnss() {
return this.employeeCnss;
}
public void setEmployeeCnss(String employeeCnss) {
this.employeeCnss = employeeCnss;
}
@Column(name = "employeeCV", length = 45)
public String getEmployeeCv() {
return this.employeeCv;
}
public void setEmployeeCv(String employeeCv) {
this.employeeCv = employeeCv;
}
@Column(name = "employeePhoto", length = 45)
public String getEmployeePhoto() {
return this.employeePhoto;
}
public void setEmployeePhoto(String employeePhoto) {
this.employeePhoto = employeePhoto;
}
@Column(name = "employeeSalaire", length = 45)
public String getEmployeeSalaire() {
return this.employeeSalaire;
}
public void setEmployeeSalaire(String employeeSalaire) {
this.employeeSalaire = employeeSalaire;
}
我的服务是这样的:
interface EmployeeRepository extends Repository<Employee, Long> {
Page<Employee> findAll(Pageable pageable);
Employee findByEmployeeNameAndEmployeeCin(String employeeName, String cin);
然后我在 com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'employee0_.employee_adress' in 'field list' 上收到此错误
我的数据库已正确生成,并且与生成的 bean 相同! 我真的不明白这是什么问题!所以请任何人都可以帮我解决这个问题? 谢谢大家,如果您需要任何其他信息,请问我
最佳答案
正如另一个 answer 中指出的那样:
By default Spring uses
org.springframework.boot.orm.jpa.SpringNamingStrategy
to generate table names. This is a very thin extension oforg.hibernate.cfg.ImprovedNamingStrategy
. The tableName method in that class is passed a source String value but it is unaware if it comes from a@Column.name
attribute or if it has been implicitly generated from the field name.The ImprovedNamingStrategy will convert CamelCase to SNAKE_CASE where as the EJB3NamingStrategy just uses the table name unchanged.
If you don't want to change the naming strategy you could always just specify your column name in lowercase:
@Column(name="testname")
另外,您确定该列是“employeeaddress”而不是“employeeaddress”吗?
关于java - 带有 Spring 数据 JPA : could not extract ResultSet 的 Spring Boot,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36464072/