我有两个表:
发布:
id | body | author | type | date
1 | hi! | Igor | 2 | 04-10
2 | hello! | Igor | 1 | 04-10
3 | lol | Igor | 1 | 04-10
4 | good! | Igor | 3 | 04-10
5 | nice! | Igor | 2 | 04-10
6 | count | Igor | 3 | 04-10
7 | left | Igor | 3 | 04-10
8 | join | Igor | 4 | 04-10
喜欢:
id | author | post_id
1 | Igor | 2
2 | Igor | 5
3 | Igor | 6
4 | Igor | 8
我想做一个查询,返回 Igor 发布的类型 2、3 或 4 的帖子数量以及 Igor 发布的点赞数量,所以,我做了:
SELECT COUNT(DISTINCT p.type = 2 OR p.type = 3 OR p.type = 4) AS numberPhotos, COUNT(DISTINCT l.id) AS numberLikes
FROM post p
LEFT JOIN likes l
ON p.author = l.author
WHERE p.author = 'Igor'
预期的输出是:
array(1) {
[0]=>
array(2) {
["numberPhotos"]=>
string(1) "6"
["numberLikes"]=>
string(2) "4"
}
}
但是输出是:
array(1) {
[0]=>
array(2) {
["numberPhotos"]=>
string(1) "2"
["numberLikes"]=>
string(2) "4" (numberLikes output is right)
}
}
那么,如何做到这一点?
最佳答案
问题是 p.type = 2 OR p.type = 3 OR p.type = 4
求值为 1
或 0
,所以只有 2 个可能的不同计数。
要解决此问题,您可以使用 case
语句:
COUNT(DISTINCT case when p.type in (2,3,4) then p.id end)
关于mysql - 带 COUNT 的 LEFT JOIN 返回意外值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36538007/