java - EclipseLink 在从 createNativeQuery 获取结果集之前随机触发查找查询

Question

EclipseLink 的奇怪行为(Eclipse Persistence Services - 2.1.1.v20100817-r8050)，我有一个 false(虚拟/不是数据库中的实际表)实体类来保存从 createNativeQuery(query,entity.class) 返回的结果集 @实体 公共(public)类 VirtualTable 实现可序列化 { 私有(private)静态最终长serialVersionUID = 1L;

@Id
@Column(name = "ROW")
private Integer row;

@Column(name = "ABC")
private String abc= null

@Column(name = "XYZ")
private String xyz= null

下面是我获取结果集的代码 我已将entityClass 设置为VirtualTable.class

/**
 * Get a list of entity objects by a native query.
 * 
 * @param nativeQueryString the query.
 * @param qryParamList the parameters for the query. Must be in the  same    order as listed in the query.
 * @param entityClass the Class of the entity object. The entityClass    field must be mapped to the 
 *        column names from the query result set.
 * @return a list of entity object of class entityClass
 */
@SuppressWarnings("rawtypes")
public static List getObjectListByNativeQuery(String nativeQueryString,
        List<Object> qryParamList, Class entityClass) {
    EntityManager em =  ReportRepository.getEntityManager(SqlConstants.PERSISTENCE_UNIT_NAME_PODR_RPT  );

    //populate the parameter list
    logger.info("em test inside query"+ em.hashCode()   +"                  "+nativeQueryString + ", with ref class: " + entityClass.getName());
    Query query = em.createNativeQuery(nativeQueryString, entityClass);

    if(qryParamList != null && qryParamList.size() > 0) {
        for(int i=0; i< qryParamList.size(); i++) {
            Object param = qryParamList.get(i);
            //the native query parameters must start with 1 
            query.setParameter(i+1, param);
        }
    }
    List resultList = query.getResultList();
            return resultList;
}enter code here

在返回结果集之前，JPA 尝试自行触发查找查询，并且由于该表不在数据库中，因此它会抛出表未找到的错误。 我在 persistence.xml 中使用 SOFT 缓存，而不是它是一个简单的 JPA 实现。 请让我知道如何避免 JPA 对此特定实体类进行查询并定义它不是实际的数据库表。我想避免手动映射，我不会在任何地方保留这个虚拟表，只是获取结果集并写入 Excelsheet

错误日志如下

  [7/21/16 2:46:43:455 EDT] 0007f794 SystemOut     O 2016-07-21   02:46:43.455 [WARN]     org.eclipse.persistence.session.podr02_user=PODRRPT.internalLog:588@PODRSchedWorkManager.Alarm Pool : 12  -  Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.1.1.v20100817-r8050): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist

Error Code: 942
Call: SELECT ROW, ABC, XYZ FROM VIRTUALTABLE WHERE (ROW = ?)
bind => [79]
Query: ReadObjectQuery(referenceClass=VirtualTable )

[7/21/16 2:46:43:455 EDT] 0007f794 SystemOut     O 2016-07-21   02:46:43.455   [ERROR]   com.bmo.cm.common.framework.service.AbstReportFileGenerator.generateReportFil    e:88@PODRSchedWorkManager.Alarm Pool : 12  - Exception   [EclipseLink-4002] (Eclipse Persistence Services - 2.1.1.v20100817-r8050): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist

Error Code: 942
Call: SELECT ROW, ABC, XYZ FROM VIRTUALTABLE WHERE (ROW = ?)
bind => [79]
Query: ReadObjectQuery(referenceClass=VirtualTable )

Answer 1

您不应该为此使用实体，因为实体需要 JPA 来管理和跟踪它们的更改，需要对象标识和缓存。相反，如果使用 JPA 2.1，您应该使用构造函数表达式来使用 ConstructorResult 构建 pojo在SqlResultSetMapping内