java - 如何使用 OOP 打印 arrayList 中的最小值？

Question

我原本期望获得最短的运行时间，但它却打印了 arrayList 中的最后一个主菜。我正在尝试为狗打印一个特定的类(class)，当我输入类(class)代码时，它就会起作用。然而，最低的运行时间似乎不起作用。

示例数据

拉兹洛 12.2

凛34.2

Yu 23.3 - 当 Lazlo 应该是获胜狗时，这将被打印为获胜狗。

获胜的狗应该有最短的运行时间，但它会读取最后读取的行并将其打印出来。

private void winningDog(String dogsCode) 
{
    double runTime = 300;
    String winningDog = "";
    double winningTime = 0;
    for (Dogs dog: dogsList)
    {
        if(runTime > dog.getTotalTime() && (dog.getCourseCode().equalsIgnoreCase(dogsCode)))
        {
            winningTime = dog.getTotalTime();
            winningDog = dog.getName();
        }

    }
    System.out.printf("%n%s%17s%20s%1.2f%n", 
          "Winning dog", winningDog,"Time " , winningTime);

}

Answer 1

假设您的 dog.getTotalTime() 没有负值，您可以更改代码

winningTime = Double.MAX_VALUE; //assigning MAX value to ensure the condition is met at least once(unless all your time values are MAX_VALUE)

然后将您的条件更新为

if(runTime > dog.getTotalTime()..

到

if(winningTime > dog.getTotalTime().. // this would compare winningTime and you're setting the same is the condition matches