java - 更新的信息没有反射(reflect)在mysql数据库中

Question

我通过引用此博客设置了一个项目，但我没有使用 Maven，而是使用了 gradle。 Registration and Login Example with Spring Security, Spring Data JPA, Spring Boot

一切正常，除了更新 Mysql 数据库中的值不起作用。

我创建了一个请求映射器来更新用户信息。我已检查请求正文不为空并且具有所有值。另外，我收到的响应状态为“成功”。但是当我在 Mysql 数据库中看到似乎没有任何更新。我的请求映射器如下。

@RequestMapping(value = "/updateRegistration", method = RequestMethod.POST)
public Map<String, Object> updateRegiatration(@RequestBody Map<String, Object> requestBody) {
    Map<String, Object> response = new HashMap<>();
    try {
        UUID userId = UUID.fromString((String) requestBody.get("userId"));
        if (userId != null) {
            User user = userRepository.findOne(userId);
            user.setFullName((String) requestBody.get("fullName"));
            user.setPostOrDesignation((String) requestBody.get("designation"));
            user.setCurrentComapny((String) requestBody.get("companyName"));
            user.setState((String) requestBody.get("state"));
            user.setCity((String) requestBody.get("city"));
            user.setShortInfo((String) requestBody.get("shortInfo"));
            user.setEmail((String) requestBody.get("email"));
            user.setAddress((String) requestBody.get("address"));
            userRepository.save(user);
            response.put("STATUS", "SUCCESS");
            response.put("STATUS_MESSAGE", "Successfully updated Information.");
        } else {
            response.put("STATUS", "ERROR");
            response.put("STATUS_MESSAGE", "Something went wrong while updating information.");
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
    return response;
}

由于我是java和spring的新手，我无法弄清楚这里发生了什么。 我怀疑这是因为应用程序中使用了“hsqldb”。 这是 build.gradle 文件。

    buildscript {
    repositories {
        mavenCentral()
    }
    dependencies {
        classpath("org.springframework.boot:spring-boot-gradle-   plugin:1.5.2.RELEASE")
        classpath 'mysql:mysql-connector-java:5.1.37'
    }
    }

    apply plugin: 'java'
    apply plugin: 'eclipse'
    apply plugin: 'idea'
    apply plugin: 'org.springframework.boot'

    jar {
        baseName = 'gs-accessing-data-mysql'
        version =  '0.1.0'
    }

    repositories {
        mavenCentral()
    }

    sourceCompatibility = 1.8
    targetCompatibility = 1.8

    dependencies {

    compile("org.springframework.boot:spring-boot-starter-web")

    // JPA Data (We are going to use Repositories, Entities, Hibernate, etc...)
    compile 'org.springframework.boot:spring-boot-starter-data-jpa'

    // Use MySQL Connector-J
    compile 'mysql:mysql-connector-java'

    testCompile('org.springframework.boot:spring-boot-starter-test')

    compile 'org.springframework.boot:spring-boot-starter-security'
    runtime 'org.hsqldb:hsqldb:2.3.1'
    compile 'org.apache.logging.log4j:log4j-api:2.0-beta9'
    compile 'org.apache.logging.log4j:log4j-core:2.0-beta9'
    compile group: 'javax.servlet', name: 'javax.servlet-api', version: '3.1.0'
    compile("org.apache.tomcat.embed:tomcat-embed-jasper")

    compile('javax.servlet.jsp.jstl:javax.servlet.jsp.jstl-api:1.2.1') {
        transitive = false
    }
    compile('org.glassfish.web:javax.servlet.jsp.jstl:1.2.1') {
        transitive = false
    }
}

我还设置了 application.properties 文件如下

spring.datasource.url=jdbc:mysql://localhost/test
spring.datasource.username=root
spring.datasource.password=abc123
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.mvc.view.prefix: /
spring.jpa.show-sql=true
spring.jpa.hibernate.ddl-auto=create

Answer 1

一般来说，您需要一个事务服务层。

@Service
@Transactional
public class MyService {
}

简而言之:

• 声明存储库
• 声明使用这些存储库的事务服务
• 在 Controller 内使用您的服务

为了让您的代码以快速而肮脏的方式工作，请尝试使用 @Transactional 注释您的 updateRegiatration 方法:

@Transactional
@RequestMapping(value = "/updateRegistration", method = RequestMethod.POST)
public Map<String, Object> updateRegiatration(@RequestBody Map<String, Object> requestBody) {
}

无论如何，如果您查看示例代码，您会看到这个服务层:

@Service
public class UserDetailsServiceImpl implements UserDetailsService{
    @Autowired
    private UserRepository userRepository;

    @Override
    @Transactional(readOnly = true)
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        User user = userRepository.findByUsername(username);

        Set<GrantedAuthority> grantedAuthorities = new HashSet<>();
        for (Role role : user.getRoles()){
            grantedAuthorities.add(new SimpleGrantedAuthority(role.getName()));
        }

        return new org.springframework.security.core.userdetails.User(user.getUsername(), user.getPassword(), grantedAuthorities);
    }
}

Controller 使用服务，而不是存储库:

@Controller
public class UserController {
    @Autowired
    private UserService userService;

    @Autowired
    private SecurityService securityService;