php - 从php中的存储过程中获取值

Question

这是我的SP:

DELIMITER $$

CREATE DEFINER=FUNCTION `test`(p_begin varchar(10),p_end varchar(10),p_code varchar(2)) RETURNS varchar(10) CHARSET latin1
BEGIN
    DECLARE V_ADA VARCHAR(8);
    DECLARE V_LAST VARCHAR(8);
    DECLARE V_NIK  VARCHAR(8);

    select NIK INTO V_NIK from absen where join_date >= p_begin and join_date<= p_end AND company_id=p_code ORDER BY NIK DESC LIMIT 1 ;

    SET V_NIK=V_NIK+1;
    return V_NIK;
END

我正在尝试使用 php 获取返回值:

$query=$this->db->query("select test(\"$begin\",\"$end\", \"$code\")")->result();

    var_dump($query);
    die;

结果是:

array(1) { [0]=> object(stdClass)#20 (1) { ["test("2007-01-01","2007-12-31", "1")"]=> string(7) "118" } } 

我的问题是我想从存储过程(“118”)中获取值，但我不知道如何将对象更改为字符串。

Answer 1

试试这个:

$query=$this->db->query("select test(\"$begin\",\"$end\", \"$code\")")->result();

// Cast object to array (also you can try get_object_vars() to do that)
$query = (array)$query[0];

// Get the last value from array (it the only on so it is OK)
echo end($query);

也许会有帮助..