我是一个学习编码的新人!
我的扫描仪有问题,我需要它在无效字符上“重置”。
我的代码:
public class Lemonade {
static int m = 150;
private static Scanner scan;
public static void main(String[] args) {
int day = 1;
for(int gameover = m; gameover > 0; day++) {
int Random = (int) (Math.random() * 100);
if(Random <= 25) {
System.out.println("Great Chance!");
System.out.println("--------------------------------");
}
else if(Random <= 50) {
System.out.println("Good Chance!");
System.out.println("--------------------------------");
}
else if(Random <= 75) {
System.out.println("Bad Chance!");
System.out.println("--------------------------------");
}
else if(Random <= 100) {
System.out.println("Awful Chance!");
System.out.println("--------------------------------");
}
int count = 0;
int none = 0;
scan = new Scanner(System.in);
System.out.println("Enter a number between 0 and " + m + "!");
count = scan.nextInt();
if(count >= none && count <= m) {
System.out.println("You entered " + count + "!");
System.out.println("--------------------------------");
day = day + 1;
m = m - count;
System.out.println("Day " + day);
}
else {
System.out.println("Enter a number between 0 and " + m + ".");
count = scan.nextInt();
}
}
}
}
现在我的问题是如何在“f”等无效字符上“重置”它,因为扫描仪只接受数字。
感谢您的帮助!
最佳答案
如果我理解正确的话,那么这就是您正在寻找的东西, 如果用户输入无效字符而不是 int,则会抛出 InputMismatchException。您可以使用循环,直到用户输入整数
import java.util.Scanner;
import java.util.InputMismatchException;
class Example
{
public static void main(String args[])
{
boolean isProcessed = false;
Scanner input = new Scanner(System.in);
int value = 0;
while(!isProcessed)
{
try
{
value = input.nextInt();
//example we will now check for the range 0 - 150
if(value < 0 || value > 150) {
System.out.println("The value entered is either greater than 150 or may be lesser than 0");
}
else isProcessed = true; // If everything is ok, Then stop the loop
}
catch(InputMismatchException e)
{
System.out.print(e);
input.next();
}
}
}
}
如果这不是您要找的,请告诉我!
关于java - 我需要 Java 扫描仪 'reset' 修复无效字符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45355699/