我正在 oncreate 中创建一个动态按钮,我没有在 XML 中放置任何按钮。
LinearLayout table = (LinearLayout)findViewById(R.id.linearlayout);
Button btnAttendance,btnSched;
btnAttendance = new Button(this);
btnSched = new Button(this);
btnAttendance.setOnClickListener(this);
btnSched.setOnClickListener(this);
table.addView(btnAttendance);
table.addView(btnSched);
//这是我在实现监听器时创建的 OnClick 方法:
@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub
BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
switch (arg0.getId()) {
case 1: // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
fetchRiddles.execute("0,"+username);
break;
case 2:
fetchRiddles.execute("1,"+username);
break;
}
如何使用 switch 确定点击了哪个按钮?我的按钮是动态创建的,无需在 xml 中放置任何按钮。
最佳答案
您可以通过编程方式设置 ID:
btnAttendance = new Button(this);
btnAttendance.setId(100);
btnSched = new Button(this);
btnSched.setId(200);
然后比较:
@Override
public void onClick(View arg0) {
// TODO Auto-generated method stub
BackgroundWorker fetchRiddles = new BackgroundWorker(DashActivity.this,"retrieveRiddles");
switch (arg0.getId()) {
case 100: // in this case i usually put "R.id.Button1:" but my problem is that my buttons are dynamic
fetchRiddles.execute("0,"+username);
break;
case 200:
fetchRiddles.execute("1,"+username);
break;
}
关于java - android中如何判断点击了哪个动态按钮?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47493164/