java - 读取特殊鼠标按钮

Question

我有兴趣捕获来自资源管理器鼠标按钮的输入(鼠标侧面的特殊按钮通常用于在网络浏览器上前进和后退)。

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.layout.Pane;
import javafx.stage.Stage;
import javafx.scene.input.MouseButton;
import static java.lang.System.*;

public class MouseThing extends Application
{
    @Override
    public void start(Stage stage) throws Exception
    {
        Pane pane = new Pane();

        pane.setOnMousePressed(e -> {
            if(e.getButton() == MouseButton.PRIMARY)
                out.println("LEFT"); 
            if(e.getButton() == MouseButton.SECONDARY)
                out.println("RIGHT");      
            if(e.getButton() == MouseButton.MIDDLE)
                out.println("MIDDLE");    
            if(e.getButton() == MouseButton.NONE)
                out.println("OTHER");  
            // How read explorer buttons?  
            out.println("click");
        });

        Scene scene = new Scene(pane, 300, 100);
        stage.setTitle("Demo");
        stage.setScene(scene);
        stage.show();
    }
}

仅举个例子，我想记录一下前进和后退按钮被激活。此时我可以实现的唯一交互是左键、右键和中键单击。按鼠标上的前进和后退按钮甚至不会注册点击打印。

有一篇关于 Javascript 的文章:JS special mouse buttons ，但它对我的目的没有用。

Answer 1

自 JavaFX 12 起，forward和 back鼠标上的按钮已被识别，因此您可以执行以下操作:

pane.setOnMousePressed(e -> {
    if(e.getButton() == MouseButton.PRIMARY)
        out.println("LEFT");
    if(e.getButton() == MouseButton.SECONDARY)
        out.println("RIGHT");
    if(e.getButton() == MouseButton.MIDDLE)
        out.println("MIDDLE");
    if(e.getButton() == MouseButton.BACK)
        out.println("BACK");
    if(e.getButton() == MouseButton.FORWARD)
        out.println("FORWARD");
    if(e.getButton() == MouseButton.NONE)
        out.println("NONE");  
    out.println("click");
});