我的作业要求我编写一个程序,让用户输入 10 名球员的姓名、年龄、位置和击球率。 (为了减少困惑,我让程序只输入3个玩家)。然后,程序应该仅检查并显示那些 25 岁以下且击球率为 0.280 或更高的玩家的统计数据,然后按年龄顺序显示它们。
我的代码(如下所示)在选择选项 2 之前一直运行良好。它不排序或显示任何内容。如果有人能帮助我,那就意义重大。关于我的代码的任何总体建议也将非常有帮助。谢谢。
import java.io.*;
import java.util.Scanner;
public class BlueJays {
static String name[] = new String[3]; //Name Array that can hold 10 names
static int age[] = new int[3]; //Age Array that can hold 10 ages
static String position[] = new String[3]; //Position Array that can hold 10 positions
static double average[] = new double[3]; //Average Array the can hold 10 batting averages
static int x, i;
//Main Method
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int menuChoice = 1;
System.out.print("Hello and Wlecome to Blue Jay Java Sort");
while (menuChoice != 3) {
System.out.print("\rEnter Menu Choice\n");
System.out.print("**********************");
System.out.print("\r(1) => Enter Blue Jay Data \n");
System.out.print("(2) => Display Possible Draft Choices \n");
System.out.print("(3) => Exit \r");
//try-catch statement for each case scenario
try {
menuChoice = Integer.parseInt(br.readLine());
} catch (IOException ie) {
ie.printStackTrace();
}
switch(menuChoice) {
case 1:
inputInfo();
break;
case 2:
inputSort();
break;
case 3:
return;
}
}
}
public static void inputInfo() throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
Scanner p = new Scanner(System.in);
//loop to request to fill array
for (x = 0; x < 3; x++) {
//Ask for player name
System.out.print("\rEnter player full name: ");
//Read input and store name in an Array
name[x] = in.readLine();
//Ask for player age
System.out.print("Enter age of player: ");
//Read input and store age in an Array
age[x] = p.nextInt();
//Ask for position of player
System.out.print("Enter player position: ");
//Read input and store position in an Array
position[x] = in.readLine();
//Ask for batting average of player
System.out.print("Enter batting average of player: ");
//Read input and store batting average in an Array
average[x] = p.nextDouble();
}
}
public static void inputSort() {
int smallest, temp;
//Selection Sort
for (x = 0; x < 3 - 1; ++x) {
smallest = x;
for(i = x + 1; i < 10; ++i) {
if (age[i] < age [smallest]) {
smallest = i;
}
}
temp = age [x];
age [x] = age [smallest];
age [smallest] = temp;
}
System.out.println(" Name " + " -----" + " Age " + "-----" + " Position " + "-----" + "Batting Average ");
for (x = 0 ; x < 3; x++) {
if (age[x] <= 25 && average[x] >= .280) {
System.out.println( name[x] + " ----- " + age[x] + " ----- " + position[x] + " ----- " + average[x]);
}
}
//Close Main()
}
//Close Class
}
`
最佳答案
修改:
这里您需要对程序进行一些小的更改,如下所示:
- 在
inputSort()
方法,您需要将 for 循环条件从for(i = x + 1; i < 10; ++i)
更改为至for(i = x + 1; i < 3; ++i)
。
您一定收到一条错误消息 ArrayIndexOutOfBound
因为您试图访问不存在的索引值。
public class BlueJays {
static String name[] = new String[3]; //Name Array that can hold 10 names
static int age[] = new int[3]; //Age Array that can hold 10 ages
static String position[] = new String[3]; //Position Array that can hold 10 positions
static double average[] = new double[3]; //Average Array the can hold 10 batting averages
static int x, i;
//Main Method
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int menuChoice = 1;
System.out.print("Hello and Wlecome to Blue Jay Java Sort");
while (menuChoice != 3) {
System.out.print("\rEnter Menu Choice\n");
System.out.print("**********************");
System.out.print("\r(1) => Enter Blue Jay Data \n");
System.out.print("(2) => Display Possible Draft Choices \n");
System.out.print("(3) => Exit \r");
//try-catch statement for each case scenario
try {
menuChoice = Integer.parseInt(br.readLine());
} catch (IOException ie) {
ie.printStackTrace();
}
switch(menuChoice) {
case 1:
inputInfo();
break;
case 2:
inputSort();
break;
case 3:
return;
}
}
}
public static void inputInfo() throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
Scanner p = new Scanner(System.in);
//loop to request to fill array
for (x = 0; x < 3; x++) {
//Ask for player name
System.out.print("\rEnter player full name: ");
//Read input and store name in an Array
name[x] = in.readLine();
//Ask for player age
System.out.print("Enter age of player: ");
//Read input and store age in an Array
age[x] = p.nextInt();
//Ask for position of player
System.out.print("Enter player position: ");
//Read input and store position in an Array
position[x] = in.readLine();
//Ask for batting average of player
System.out.print("Enter batting average of player: ");
//Read input and store batting average in an Array
average[x] = p.nextDouble();
}
}
public static void inputSort() {
int smallest, temp;
//Selection Sort
for (x = 0; x < 3 - 1; ++x) {
smallest = x;
for(i = x + 1; i < 3; ++i) {
if (age[i] < age[smallest]) {
smallest = i;
}
}
temp = age [x];
age [x] = age [smallest];
age [smallest] = temp;
}
System.out.println(" Name " + " -----" + " Age " + "-----" + " Position " + "-----" + "Batting Average ");
for (x = 0 ; x < 3; x++) {
if (age[x] <= 25 && average[x] >= .280) {
System.out.println( name[x] + " ----- " + age[x] + " ----- " + position[x] + " ----- " + average[x]);
}
}
//Close Main()
}
}
关于java - 数组和排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50539498/