我正在开发一个用于联系人的应用程序，为此我使用 sqlite 数据库来存储姓名和号码，因此我想过滤姓名和号码以搜索哪些 我尝试过这个查询但是 这对我不起作用 对于我使用的问题有什么解决方案吗？
public boolean onQueryTextChange(String newText) {
try {
final String temp = newText.toLowerCase();
final ArrayList<Map> map1 = new ArrayList();
try {
dbhelper =new FeedReaderDbHelper(getActivity());
SQLiteDatabase db=dbhelper.getReadableDatabase();
String projection[]={FeedReaderContract.FeedEntry.COLUMNS_TITLE,FeedReaderContract.FeedEntry.COLUMN_SUB_TITLE};
Cursor cursor =db.query(FeedReaderContract.FeedEntry.TABLE_NAME,projection ,FeedReaderContract.FeedEntry.COLUMNS_TITLE+"= ?",new String[]{newText},null,null,null);
while(cursor.moveToFirst()){
String name = cursor.getString(cursor.getColumnIndex(FeedReaderContract.FeedEntry.COLUMNS_TITLE));
String number = cursor.getString(cursor.getColumnIndex(FeedReaderContract.FeedEntry.COLUMN_SUB_TITLE));
Map<String, Object> map = new HashMap();
map.put(name, number);
if (name.toLowerCase().contains(temp)) {
map1.add(map);
Phone.this.adapter.Filter(map1);
}
} }
catch(Exception e){
System.out.print(Retriving_list);
}
}catch(Exception e){
Toast.makeText(getActivity(), First_Retrive_Data, Toast.LENGTH_SHORT).show();
}
//DbHelper类
公共(public)类 FeedReaderDbHelper 扩展 SQLiteOpenHelper{
public static final int DB_VERSION =1;
public static String getDataBASE_NAME() {
return DataBASE_NAME;
}
public static void setDataBASE_NAME(String dataBASE_NAME) {
DataBASE_NAME = dataBASE_NAME;
}
public static String DataBASE_NAME;
Context context;
private static final String SQL_CREATE_ENTRIES =
"CREATE TABLE " + FeedReaderContract.FeedEntry.TABLE_NAME + "(" +
FeedReaderContract.FeedEntry._ID + "INTEGER PRIMARY KEY," +
FeedReaderContract.FeedEntry.COLUMNS_TITLE + " TEXT ," +
FeedReaderContract.FeedEntry.COLUMN_SUB_TITLE + " TEXT UNIQUE)";
private static final String SQL_DELETE_ENTRIES =
"DROP TABLE IF EXISTS " + FeedReaderContract.FeedEntry.TABLE_NAME;
public FeedReaderDbHelper(Context context) {
super(context, FeedReaderDbHelper.getDataBASE_NAME(), null, DB_VERSION);
this.context=context;
}
@Override
public void onCreate(SQLiteDatabase sqLiteDatabase) {
sqLiteDatabase.execSQL(SQL_CREATE_ENTRIES);
}
void addContactValues(FeedReaderDbHelper dbhelper ,String name ,String number){
SQLiteDatabase db= dbhelper.getWritableDatabase();
ContentValues values =new ContentValues();
values.put(FeedReaderContract.FeedEntry.COLUMNS_TITLE ,name);
values.put(FeedReaderContract.FeedEntry.COLUMN_SUB_TITLE,number);
long rows= db.insertWithOnConflict(FeedReaderContract.FeedEntry.TABLE_NAME,null,values,SQLiteDatabase.CONFLICT_IGNORE);
if (rows==-1){
// Toast.makeText(context, String.valueOf(rows)+"not interested", Toast.LENGTH_SHORT).show();
}
else{
Toast.makeText(context, String.valueOf(rows)+"inserted", Toast.LENGTH_SHORT).show();
}
}
@Override
public void onUpgrade(SQLiteDatabase sqLiteDatabase, int i, int i1) {
sqLiteDatabase.execSQL(SQL_DELETE_ENTRIES);
onCreate(sqLiteDatabase);
}
}
最佳答案
目前尚不清楚您想要什么，但如果您只想获取具有给定值的行，它应该如下所示:
String mSearchString = "what do you want to search";
String selection = setupSelectionString();
cursor = database.query(NoteContract.NoteEntry.NOTES_TABLE_NAME, projection, selection, selectionArgs,
null, null, sortOrder);
private String setupSelectionString() {
String selection = null;
if (mSearchString != null) {
selection = FeedReaderContract.FeedEntry.COLUMNS_TITLE + " LIKE '%"
+ mSearchString + "%'"
+ " OR " + FeedReaderContract.FeedEntry.COLUMN_SUB_TITLE + " LIKE '%"
+ mSearchString + "%'";
}
return selection;
它适用于我的应用
关于java - 如何在Sqlite数据库中搜索值？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/52121638/