当我像这样传递文件名时,它不会获取数据..如何在方法中动态传递文件名?
public static String fetchData(int index,int rowNum, int cellNum,String FileName) throws FileNotFoundException {
File filePath = new File(System.getProperty("user.dir") + "/InEdge_Files/ExcelData/" + FileName + ".xlsx");
fis = new FileInputStream(filePath);
sheet = workbook.getSheetAt(index);
value = sheet.getRow(rowNum).getCell(cellNum).getStringCellValue();
return value;
}
...传递我使用的数据时,driver.get(fetchData(0,1,2,"Data");
最佳答案
String urlToOpen = fetchData(0,1,2,"Data");
driver.navigate().to(urlToOpen);
关于java - 获取数据时动态传递文件名? Selenium -java,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52435751/