java - 如果 JSON 响应结果为 0/11，如何将用户发送到 servlet 内的 .html 页面

Question

假设用户使用正确的凭据登录我的网站，结果是

{"ticketStatus":"Valid","requestId":"73","result":0,"resultText":"Valid"}

{"ticketStatus":"Invalid","requestId":"8","result":11,"resultText":"Invalid"}

如何才能检索“有效/无效”或“0/11”，以便将用户发送到 valid.html/invalid.html(其中包含您已成功/未成功登录)。 如果它是“无效”或“11”(两者之一，取决于我可以分配的内容)，情况也是如此。我只是不知道应该如何选择或选择什么才能将其放入 if 语句中。这是我的代码。

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {


}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    //index.html form user input
     String fname = request.getParameter("firstName");
    String lastName = request.getParameter("lname");
    String ticketNummer = request.getParameter("ticketnr");

    JsonParser parser = new JsonParser();

    URL object=new URL(url);

    String ticketCheck = "{\"function\":\"Check\",\"teamId\":\"IC106-2\",\"teamKey\":\"1b3741ccf6d9ec5245055370125d901e\",\"requestId\":\""+REQ_ID+"\",\"firstName\":\""+fname+"\",\"lastName\":\""+lastName+"\",\"ticketNumber\":\""+ticketNummer+"\"}";

    System.out.println(ticketCheck);

    HttpURLConnection con = (HttpURLConnection) object.openConnection();
    con.setDoOutput(true);
    con.setDoInput(true);
    con.setRequestProperty("Content-Type", "application/json");
    con.setRequestProperty("Accept", "application/json");
    con.setRequestMethod("POST");

    OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
    writer.write(ticketCheck);
    writer.flush();

    StringBuilder sb = new StringBuilder();
    String jsonResponseString = sb.toString();
    JsonElement jsonTree = parser.parse(jsonResponseString);

    int HttpResult = con.getResponseCode();
    if (HttpResult == HttpURLConnection.HTTP_OK) {
        BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream(), "utf-8"));
        String line;
        while ((line = br.readLine()) != null) {
            sb.append(line + "\n");
        }
        br.close();
        System.out.println("" + sb.toString());
    } else {
        System.out.println(con.getResponseMessage());
    }







}

Answer 1

通过解析响应解决了问题。

int HttpResult = con.getResponseCode();
    if (HttpResult == HttpURLConnection.HTTP_OK) {
        BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream(), "utf-8"));
        String line;
        while ((line = br.readLine()) != null) {
            sb.append(line + "\n");
        }
        br.close();
        System.out.println("" + sb.toString()); //the responsemessage
    } else {
        System.out.println(con.getResponseMessage());
    }


    String jsonStr = sb.toString();
    JSONObject jsonObj = new JSONObject(jsonStr);
    String ticketstat = jsonObj.getString("ticketStatus"); //get ticketStatus value
    System.out.println(ticketstat);

    if (ticketstat .equals("Invalid")){ //code here for w/e you want to do with invalid


    }

}