我正在尝试找到一个使用 X-Forwarded-* header 构建新链接的解决方案。
public class ApiUriBuilderTest {
private MockHttpServletRequest request = new MockHttpServletRequest();
private HttpRequest httpRequest = new ServletServerHttpRequest(request);
@Before
public void setUp() throws Exception {
request.setScheme("http");
request.setServerName("localhost");
request.setServerPort(80);
request.setRequestURI("/mvc-showcase");
request.addHeader("X-Forwarded-Proto", "https");
request.addHeader("X-Forwarded-Host", "84.198.58.199");
request.addHeader("X-Forwarded-Port", "443");
request.setContextPath("/mvc-showcase");
request.setServletPath("/app");
request.setRequestURI("/mvc-showcase/app/uri/of/request?hello=world&raw#my-frag");
httpRequest = new ServletServerHttpRequest(request);
}
@Test
public void test() {
String uri = ForwardedContextPathServletUriComponentsBuilder.fromRequest(request).build().toUriString();
assertThat(uri, is("https://84.198.58.199:443"));
}
@Test
public void test_uri_components_builder() throws URISyntaxException {
UriComponents result = UriComponentsBuilder.fromHttpRequest(httpRequest).build();
assertEquals("https://84.198.58.199:443", result.toString());
}
但返回值为“https://84.198.58.199/mvc-showcase/app/uri/of/request?hello=world&raw#my-frag ”。我怎样才能摆脱 context-path、setvlet-path 和 request uri?
最佳答案
@Test
public void test() {
String uri = ServletUriComponentsBuilder.fromRequest(request).replacePath("relativePath").replaceQuery(null).build().toUriString();
assertThat(uri, is("https://84.198.58.199:8080/relativePath"));
}
有帮助。
关于java - 如何使用 X-Forwarded-* header 创建没有上下文路径的 URI?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55745051/