java - 如何将 "01/30/2018 02:29:23 PM"转换为smalldatetime格式？我在我的应用程序中使用 MSSQL，并且该列是smalldatetime 格式

Question

我正在尝试将格式为“01/02/2018 02:48:04 PM ”的字符串转换为smalldatetime 格式以插入到MS SQL 中。

import java.sql.Date;
import java.sql.Timestamp;
import java.time.Instant;
import java.time.LocalDate;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.time.format.DateTimeFormatterBuilder;
import java.util.Locale;

public class TimeStampTest {

    public static void main(String[] args) {
        String originalDate ="01/02/2018 02:29:23 PM";
        System.out.println(convertToSmallDatetimeFormat(originalDate));
    }

    private static Timestamp convertToSmallDatetimeFormat(String originalDate) {


        DateTimeFormatter formatter = new DateTimeFormatterBuilder()
                .parseCaseInsensitive()
                .appendPattern("MM/dd/yyyy hh:mm:ss a")
                .toFormatter(Locale.US);
        LocalDateTime localDate = LocalDateTime.parse(originalDate,formatter);

        return new Timestamp(localDate.getNano()/1000000);

    }

}

但是我意识到当我执行以下代码时

LocalDateTime localDate = LocalDateTime.parse(originalDate,formatter);

我得到了一些垃圾值2018-01-02T15:58:04

这会导致 localDate.getNano() 为 0

Answer 1

您可以使用Timestamp.valueOf

private static Timestamp convertToSmallDatetimeFormat(String originalDate) {
    DateTimeFormatter formatter = new DateTimeFormatterBuilder()
            .parseCaseInsensitive()
            .appendPattern("MM/dd/yyyy hh:mm:ss a")
            .toFormatter(Locale.US);
    LocalDateTime localDate = LocalDateTime.parse(originalDate,formatter);
    System.out.println("****"+localDate);
    return Timestamp.valueOf(localDate);
}