java - 如何用Java匹配字符串中的阿拉伯Unicode字符？

Question

大家好；

我有一个桌面 Java 应用程序，它在控制台窗口中提供以下输出:

[
{
"ew" : "ana"
"hws" : [
"\u0623\u0646\u0627"
]
}
]

我想将这个字符串:“\u0623\u0646\u0627”从整个输出中分离出来，以便仅对该字符串进行进一步处理。

我不知道该怎么做？但想法之一是使用 REGEX。 但我怎样才能做到这一点呢？

你能帮我吗？

Answer 1

鉴于附加信息

The output shall be arabic letters not \u064A...etc. My idea was to search the output till the \u064A... lines and convert them to arabic. Have you get my point? I don't know how to solve this, I am a beginer in java. Sorry for the confusion and thank you for your response.

输入来自http://www.google.com/transliterate/arabic?tlqt=1&langpair=en|ar&text=ana,m­asry&&tl_app=1你可以这样解决:

import java.net.*;
import java.io.*;
import java.util.*;
import java.util.regex.*;

public class URLConnectionReader {
    public static void main(String[] args) throws Exception {
    URL googleUrl = new URL("http://www.google.com/transliterate/arabic?tlqt=1&langpair=en|ar&text=ana,m­asry&&tl_app=1");
    URLConnection googleUrlc = googleUrl.openConnection();
    BufferedReader in = new BufferedReader(new InputStreamReader(googleUrlc.getInputStream()));
    String inputLine;
    Pattern wordRegex = Pattern.compile("\"(\\\\u[\\da-z]{4})+\"", Pattern.CASE_INSENSITIVE);
    Pattern charRegex = Pattern.compile("\\\\u([\\da-z]{4})", Pattern.CASE_INSENSITIVE);
    while ((inputLine = in.readLine()) != null) {
        Matcher wordMatch = wordRegex.matcher(inputLine);
        for (int i = 0; wordMatch.find(); i++) {
        StringBuffer arabicBuffer = new StringBuffer();
        Matcher charMatch = charRegex.matcher(wordMatch.group());
        for (int j = 0; charMatch.find(); j++) {
            arabicBuffer.appendCodePoint(Integer.valueOf(charMatch.group(1), 16));
        }
        if (0 < arabicBuffer.length()) {
            System.out.println(arabicBuffer.toString());
        }       
        } 
    }
    in.close(); 
    }
}