我有以下数据,我正在使用“http://commons.apache.org/jxpath/”,我想直接读取坐标:[51.464426 -0.382974] 这是纬度,lng 我如何阅读这个快速示例,我搜索周围并发现还有另一个 jsonpath 以及 jsonxpath 是否可以为我工作任何快速解决方案?
{
authenticationResultCode: "ValidCredentials"
brandLogoUri: http://dev.virtualearth.net/Branding/logo_powered_by.png
copyright: "Copyright © 2011 Microsoft and its suppliers. All rights reserved. This API cannot be accessed and the content and any results may not be used, reproduced or transmitted in any manner without express written permission from Microsoft Corporation."
-
resourceSets: [
-
{
estimatedTotal: 1
-
resources: [
-
{
__type: "Location:http://schemas.microsoft.com/search/local/ws/rest/v1"
-
bbox: [
51.46056328242933
-0.39124021297987016
51.46828871757068
-0.3747077870201298
]
name: "TW4 5AP, Hounslow, United Kingdom"
-
point: {
type: "Point"
-
coordinates: [
51.464426
-0.382974
]
}
-
address: {
adminDistrict: "England"
adminDistrict2: "Hounslow"
countryRegion: "United Kingdom"
formattedAddress: "TW4 5AP, Hounslow, United Kingdom"
postalCode: "TW4 5AP"
}
confidence: "High"
entityType: "Postcode1"
}
]
}
]
statusCode: 200
statusDescription: "OK"
traceId: "16c9b05027c4486fa3adab793cfdb97e|EWRM001665|02.00.82.2800|EWRMSNVM001812, EWRMSNVM001724"
}
最佳答案
关于java jsonxpth 解析json跳转到节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5552818/