我有一个单词列表,在标记化之后,我的列表中出现了一些我实际上不想要的空白。请提出建议...
示例字符串
String str = "3) type an \"l\" in the search field (\"bl\")"+
"4) startHistorySearch()'s previous result contains [\"blah\", \"baaa\", \"bloop\", \"bzzz\"], Satchel filters this down to [\"blah\", \"bloop\"] to match the new \"bl\" search string"+
and so on.....
这是代码和输出片段
String[] splitString = (EXAMPLE_TEST.split("[\\[\\],\\'\" \\(\\)\\{\\}\\*\\.]"));
输出
nsIAutoCompletResult, , no, , Simple, , , , so, the, QI, fails, , historyResult
在某些地方我看到这样的......
finds, 1, entry, , , blah, , , , search-suggestions, finds, , baaa, , , , bloop, , , , bzzz, , , the, autocompete, menu, shows, these, in, order, with, a, divider, between, , blah, , and, , baaa, , 3, , type, , l, , in, the, search, field, , , bl, , 4, , startHistorySearch, , , s, previous, result, contains, , , blah, , , , baaa, , , , bloop, , , , bzzz, , , , Satchel, filters, this, down, to, , , blah, , , , bloop, , , to, match, the, new, , bl, , search, string5, , nsSearchSuggestions, s, onReadyState, , , change, is, called, with, updated, search,
最佳答案
只需在表达式中添加一个 +
即可,以免在两个标记之间拆分。您还可以稍微简化表达式,不必转义字符类中的所有这些字符:
String[] splitString = (EXAMPLE_TEST.split("[\\[\\],'\" (){}*.]+"));
关于java - 标记化后列表中的空白,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13173134/