各位程序员大家好:)。
我对 Java 很陌生,如果这是 PHP,我已经这样做了:P,无论如何,我尝试在这里搜索所有答案(stackoverflow),但没有一个适合我的特定问题,或者我没有看到示例,或者我错过了一些东西......无论如何,如果您知道与我的问题类似的解决方案,请发布答案链接。
问题解决了;)
我在一个文件中有这个 XML,我需要它像这样:
<?xml version="1.0" encoding="UTF-8"?>
<events>
<event id="46" title="Ferias" start="2013-04-25" end="2013-04-26" allDay="false" editable="true"/>
<event id="47" title="Falta" start="Wed Apr 17 2013 00:00:00 GMT+0100" end="Thu Apr 18 2013 00:00:00 GMT+0100" allDay="false" editable="true"/>
<event id="48" title="Tolerancia de Ponto" start="Mon Apr 01 2013 00:00:00 GMT+0100" end="" allDay="false" editable="true"/>
<event id="49" title="Titulo teste" start="Thu Apr 11 2013 00:00:00 GMT+0100" end="Sat Apr 13 2013 00:00:00 GMT+0100" allDay="true" editable="true"/>
<event id="50" title="dfgfdgf" start="Fri Apr 12 2013 00:00:00 GMT+0100" end="Sat Apr 13 2013 00:00:00 GMT+0100" allDay="true" editable="true"/>
<event id="51" title="hghfjfghj" start="Tue Apr 16 2013 00:00:00 GMT+0100" end="Wed Apr 17 2013 00:00:00 GMT+0100" allDay="true" editable="true"/>
<event id="52" title="grande evento" start="Tue Apr 23 2013 00:00:00 GMT+0100" end="Wed May 01 2013 00:00:00 GMT+0100" allDay="true" editable="true"/>
</events>
我正在尝试添加一个带有属性的新元素“事件”,并且我正在使用它来加载和修改:
String FilePath = "D:/myxml.xml";
Document doc = openXMLfile(FilePath);
这里加载没有问题..
其中 openXMLfile 是这样的:
protected Document openXMLfile(String filepath){
Document doc = null;
try {
File fXmlFile = new File(filepath);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
doc = dBuilder.parse(fXmlFile);
} catch (Exception e) {
e.printStackTrace();
}
return doc;
}
然后在我的添加元素的函数中我这样做:
File file = new File("D:\myxml.xml");
Element event = doc.createElement("event");
event.setAttribute("test","testvalue");
doc.getDocumentElement().appendChild(event);
filePutContents(doc,file);
其中 filePutContents 我有这个功能:
protected void filePutContents(Document doc,File file){
try{
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT,"yes");
DOMSource source = new DOMSource(doc);
//StreamResult result = new StreamResult(System.out);//problem was this
StreamResult result = new StreamResult(file);//correct way
transformer.transform(source, result);
}catch(TransformerConfigurationException tce){
/*ERRO do Transformer*/
System.out.println("* Transformer Factory error");
System.out.println(" " + tce.getMessage());
Throwable x = tce;
if (tce.getException() != null)
x = tce.getException();
x.printStackTrace();
}catch(TransformerException te){
/*ERRO da Factory*/
System.out.println("* Transformation error");
System.out.println(" " + te.getMessage());
Throwable x = te;
if (te.getException() != null)
x = te.getException();
x.printStackTrace();
}
}
问题是,没有元素添加到文件中,我想要更新文件,我做错了什么?谢谢
问题已解决,我已经反射(reflect)了代码中的更改;)感谢帮助者:)
最佳答案
StreamResult result = new StreamResult(System.out);
上面的语句将输出定向到控制台 (System.out)。如果您想要更新文件,请将其指向该文件。
试试这个-
StreamResult result = new StreamResult(new FileOutputStream("somefile.xml"));
关于Java向xml文件添加具有属性的元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16144962/