嗨,我是编程新手,所以请不要 mock 我愚蠢的问题。
我编写的程序要求用户输入一个数字,然后程序应该输出从0到输入数字的所有数字(无论是正数还是负数)。 我尝试了3个不同的版本
这是我的代码:
int min = Integer.MIN_VALUE;
int max = Integer.MAX_VALUE;
int num = PutiL.validNum(min, max, "number");
//this my utility methode which check if number is in range and if it is not a double or letter
int i = 0, z;
int y = 0;
//3rd version
while (i <= num) {
for (z = 0; z < 4; z++) {
System.out.print(i + " ");
i++;
}
System.out.println();
}
//2nd version
if (num > 0) {
for (i = 0; i <= num; y++) {
for (z = 0; z < 4; z++) {
System.out.print(i + ",");
i++;
}
System.out.println();
}
} else {
for (i = 0; i > num; y--) {
for (z = 0; z < 4; z++) {
System.out.print(i + ",");
i--;
}
System.out.println();
}
}
//1st version`enter code here`
if (num > 0) {
for (i = 0; i <= num; i++)
{
System.out.print(i + ",");
}
} else {
for (i = 0; i >= num; i--) {
System.out.print(i + ",");
}
}
System.out.println();
问题是代码在用户输入数字后不会立即停止。有人会告诉我哪里出了问题吗,因为我没有更多的想法了。
这是 PutilL 方法
public static int validNum(int min, int max, String words) {
int num;
do {
System.out.println("Please enter " + words);
while (!kb.hasNextInt()) {
System.out.println("Please re-enter ");
kb.nextLine();
}
num = kb.nextInt();
if (num < min || num > max) {
System.out.println("Not in range - re-enter\tproper range is "
+ min + " - " + max);
}
} while (num < min || num > max);
return num;
}
最佳答案
//2nd version
if (num > 0)
{
for (i = 0; i <= num; y++) <== THIS MAKE INFINITE too, OKAY.. ^^, change i to stop
{
for (z = 0; z < 4; z++)
{
System.out.print(i + ",");
i++;
}
System.out.println();
}
} else
{
for (i = 0; i > num; y--) <== THIS MAKE INFINITE LOOPS, OKAY.. ^^, it must i to stop
{
for (z = 0; z < 4; z++)
{
System.out.print(i + ",");
i--;
}
System.out.println();
}
}
如果答案正确,请不要忘记接受..^^
关于java - java中如何每行输出多个数字,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16917392/