linux - 消除 LINUX 中第一个和最后一个空格或制表符

Question

我有一个 json 文件，其中列出的元素如下:

"URL": [      "R-MMU-72200"    ],

"GENES": [      "4706167874","4706170968"    ],

"NAME": [      "mRNA Editing: C to U Conversion"    ],

"ORGANISM": [      "Mus musculus"    ],

"PATH_MAP": [      "R-MMU-72200"    ]  },

我想消除括号内每个字符串开头和结尾的空格或制表符。我想要这个:

 "URL": ["R-MMU-72200"],

 "GENES": ["4706167874","4706170968"],

 "NAME": ["mRNA Editing: C to U Conversion"],

 "ORGANISM": ["Mus musculus"],

 "PATH_MAP": ["R-MMU-72200"]  },

提前致谢

Answer 1

类似这样的吗？

sed 's/\s\s//g'

结果:

"URL": ["R-MMU-72200"],