我是新手，我想使用 grep 或正则表达式搜索一个大文件，其中包含唯一 ID 的列表。
示例文件:
/icon_edit.png\" \/><\/a> AP-28992 : ABCD-1103_01 [v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/fax","<!-- 0000000000 --><a href=\"javascript:openTCEditWindow(0000,000);\"><img title=\"
TSD\" src=\"gui\/themes\/default\/images\/icon_edit.png\" \/><\/a> AP-28993 : ABCD-1103_02
[v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/traax","<!-- 0000000000 --> ABCD_110_01
应在下面进行唯一过滤，例如:
ABCD-1103
ABCD-110
最佳答案
我猜 ABCD-110 是您的输入模式，空格是分隔符
所以如果你的输入文件即。 abc.txt 就像(我修改了最后一行)
$cat abc.txt
/icon_edit.png\" \/><\/a> AP-28992 : ABCD-1103_01 [v1]","2","2012-10-27
18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/fax","<!-- 0000000000 --><a
href=\"javascript:openTCEditWindow(0000,000);\"><img title=\"
TSD\" src=\"gui\/themes\/default\/images\/icon_edit.png\" \/><\/a> AP-28993 :
ABCD-1103_02
[v1]","2","2012-10-27 18:40:47","2012-01-04 13:22:41"],
["shawn","extra\/traax","<!-- 0000000000 --> ABCD-110_01
然后进行以下工作:
$cat abc.txt | grep -ow "ABCD-110.*" | awk '{print $1}'
ABCD-1103_01
ABCD-1103_02
ABCD-110_01
关于linux - GREP 或 Regex 搜索特定系列的唯一字符，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50524120/