将行转列的 Linux 脚本

Question

我有以下数据集，需要进行一些转置。我在剧本上苦苦挣扎。任何帮助，将不胜感激。所有列/值都是动态的

文件格式:

ID    FieldName          FieldValue

1   Rooms Required?        Yes

1   Country of Meeting     US

2   Rooms Required? 

2   Country of Meeting  

3   Rooms Required? Yes

3   Country of Meeting  US

4   Rooms Required? No

4   Country of Meeting  BL

所需输出:

ID  Rooms Required? Country of Meeting

1     Yes                   US

2       

3     Yes                   US

4     No                     BL

请帮忙

Answer 1

基于由制表符 '\t' 分隔的字段的纯 awk 解决方案如下:

awk 'BEGIN { FS = "\t"; PROCINFO["sorted_in"] = "@ind_num_asc" } { if ( $1 !~ /^[0-9]+$/ ) next; A[$1][$2] = $3; H[$2] } END { printf "ID"; for (h in H) printf "\t" h; for (i in A) { printf "\n\n" i; for (j in A[i]) printf "\t" A[i][j] } print "\n" }' filename

分割:

awk 'BEGIN {
    FS = "\t"  #Set Field Separator as the Tab
    PROCINFO["sorted_in"] = "@ind_num_asc"  #Set array order as numbers
}
{
    if ( $1 !~ /^[0-9]+$/ )  #Skip all rows without numeric ID
        next
    A[$1][$2] = $3  #Store value in multi-dimensional array
    H[$2]           #Store header name
}
END {
    printf "ID"
    for (h in H)    #Print all headers found
        printf "\t" h
    for (i in A) {  #Print each record with corresponding values
        printf "\n\n" i
        for (j in A[i])
            printf "\t" A[i][j]
    }
    print "\n"
}' filename

如果需要任何进一步的解释，请告诉我。这将适用于您以任意顺序设置的任意数量的和字段。如果记录不具有所有相同的字段，您的输出可能看起来参差不齐。