php - 更新多个php文件(具体值，按文件顺序增加)

Question

执行以下场景的正确方法是什么

有 100 个文件 db01.php db100.php

其中包含此sql语句

$sql = mysql_query("select user from level2 where id BETWEEN 1 AND 350");

my gol is update value ( BETWEEN 1 AND 350 )  

通过添加 +350 从 db01.php 到 db100.php

db02.php 语句将是

   $sql = mysql_query("select user from level2 where id BETWEEN 350 AND 700");

db03.php

        $sql = mysql_query("select user from level2 where id BETWEEN 700 AND 1050");

..继续直到最后一个文件， 最好的方法是什么!

Answer 1

您可以使用 get 参数创建单个 PHP 文件，该参数指示文件的“编号”(根据您的情况，修改 BETWEEN 的开头和结尾)。

尝试创建 PHP db.php 文件:

$interval = 350;
$num = (int) $_GET["num"];

// Generate start and end (for between)
$start = (int) $interval * ($num - 1);
$end = (int) $interval * $num;

// Hack for the first number (start should be 1, not 0)
if($start == 0) $start = 1;

// Generate sql with $start and $end)
$sql = mysql_query("select user from level2 where id BETWEEN " . $start . " AND " . $end);

然后这样调用它:

http://www.yourside.com/db.php?num=1
http://www.yourside.com/db.php?num=2

等等...