user1 27913 41004 4 15:54 pts/202 00:00:02 python demo.py
user1 31916 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31917 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31918 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31919 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31920 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31921 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31922 27913 0 15:55 pts/202 00:00:00 python demo.py
user1 31923 27913 0 15:55 pts/202 00:00:00 python demo.py
有一个进程27913，我想杀死它及其所有子进程，我怎样才能让它工作？
update python script:
下面是我的demo.py
from concurrent.futures import ProcessPoolExecutor
import time
def foo(num):
time.sleep(0.5)
print(num)
if __name__ == "__main__":
while True:
with ProcessPoolExecutor(max_workers=8) as exe:
exe.map(foo, range(1,4))
最佳答案
通过进程ID杀死进程
例如:
使用此命令列出您的 python 文件 ps -A| grep python
并终止进程:kill 27913
关于linux - Linux下如何杀死一个进程及其所有子进程？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/57249614/