我想问我有一个文件,其中的数字按行和列写入:
23 54 433 65 23
44 3 32 422 43
我想将其复制到二维 int 数组中,但我不知道该怎么做。我想应用一个字符串标记函数,但如何应用它我不知道该怎么做,请指导我一点
谢谢
最佳答案
这个问题有两个答案。其中之一非常简单(假设您知道相关输入文件的列数和行数)。
for (int a=0; a<NUMROW; a++)
for (int b=0; b<NUMCOL; b++)
cin>>TWODARRAY[a][b];
所以这很简单。对于可变长度的数据输入,我想出的又长又笨拙的答案更令人兴奋。不过,我已经测试过了,它确实有效。希望每个人都能熟悉指向指针和字符串流的指针。
string in;
int** twoDArray=NULL;
int numRow=0;
int numCol=0;
string** inputHold=NULL;
int inputSize=10;
//Since we're using pointers instead of vectors,
//we have to keep track of the end of the array.
inputHold=new string*[inputSize];
while (getline(cin,in)){
//The string in now contains a line of input.
if (numRow==0)
//Assuming that the number of inputs per column is the same in each row,
//we can save on computation by only checking the number of columns once.
//Performance may be improved here- it might be more efficient to use str.find
for (string::iterator iter=in.begin(); iter!=in.end(); iter++){
if (*iter==' ')
numCol++;
}
//Store the string
inputHold[numRow]=new string(in);
numRow++;
if (numRow==inputSize) {
//If we're at the end of the array, we create a bigger one and repopulate the data.
string** tmpInput=inputHold;
int oldsize=inputSize;
inputSize=inputSize*2;
inputHold=new string*[inputSize];
for (int i=0; i<oldsize; i++){
inputHold[i]=tmpInput[i];
}
}
}
//The method that I used to determine the number of columns is mildly flawed-
//it doesn't account for the end of line. So, we increment the counter.
numCol=numCol+1;
twoDArray=new int*[numRow];
for (int a=0; a<numRow; a++)
twoDArray[a]=new int[numCol];
for (int a=0; a<numRow; a++){
istringstream parser(*(inputHold[a]));
for (int b=0; b<numCol; b++){
parser>>twoDArray[a][b];
}
}
for (int a=0; a<numRow; a++)
for (int b=0; b<numCol; b++)
cout<<twoDArray[a][b]<<endl;
有人有更简单的东西吗?
关于c++ - 将文件数据复制到 int 数组中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5793523/