linux - 使用 Linux/Unix 命令替换文件中的行 block

Question

您能帮忙提供一个可以对文件执行的命令吗:

输入-1:

/*
* Copyright (c) 1992-2013 Some comp, Inc and/or its affiliates. All rights reserved.
* Some comp PROPRIETARY/CONFIDENTIAL. Use is subject to license terms.
* Author: aaaa
* DateCreated:   aaaa
* Last Modified By: aaaa
* Modified Time:  aaaa
* File Version: aaaa
* File Path: aaaa
*/

以上所有行应删除并替换为

/*
* Copyright (c) 1992-2013 some comp, and/or its affiliates. All rights reserved.
* some comp PROPRIETARY/CONFIDENTIAL. Use is subject to license terms.
* Author: bbbb
* DateCreated:   bbbb
* Last Modified By:  bbbb
* Modified Time:  bbbb
* File Version:  bbbb
* File Path:  bbbb
*/

我的意见是，首先删除从“/”到“/”第一次出现的位置，或者从文件开头删除直到*/。 之后，替换为文件顶部的第二行行。

Answer 1

在 sed 和 awk 中使用正则表达式。 Gawk 有一个名为 gsub 的函数用于替换文本。