python - ssh paramiko 无法读取输出

Question

我正在使用 paramiko 连接到服务器，并尝试使用 channel.send 接收顺序输出。下面的脚本无法捕获 channel.recv 的输出。有什么想法吗？

import paramiko
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect("xx.xx.xx.xx",username='kshk',password='xxxxxxxx',key_filename='/home/krisdigitx/.ssh/id_rsa')
channel = ssh.invoke_shell()
channel.send('df -h\n')

while channel.recv_ready():
    outp = channel.recv(1024)
print outp

给予:

krisdigitx@krisdigitx-Dell-System-XPS-L702X:~/SCRIPTS$ python test.py 
Traceback (most recent call last):
  File "test.py", line 11, in <module>
    print outp
NameError: name 'outp' is not defined

在解释器模式下运行脚本可以工作...

>>> import paramiko
>>> ssh = paramiko.SSHClient()
>>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
>>> ssh.connect("xx.xx.xx.xx",username='kshk',password='xxxxx',key_filename='/home/krisdigitx/.ssh/id_rsa')
>>> channel = ssh.invoke_shell()
>>> channel.send('df -h\n')
6
>>> while  channel.recv_ready():
...     outp = channel.recv(1024)
... 
>>> print outp
/dec/sda
                      7.2T  6.6T  622G  92% /tmp/xxx
[kshk@server ~]$ 
>>> 

Answer 1

您可以在使用 with 语句创建的上下文管理器的范围内定义 outp。 尝试在上下文管理器套件中进行打印，即

while channel.recv_ready():
    outp = channel.recv(1024)
    print outp

或者这样做:

outp = ""
while channel.recv_ready():
    outp = channel.recv(1024)
print outp