此代码从用户处获取姓名和一个号码,并向其添加一个号码 (5150)。我不明白为什么会出现段错误。提示输入号码后出现错误。代码如下:
SECTION .data
askName: db "Enter your name: ",0
askNum: db "Enter an unsigned number no more than four digits: ",0
fResultP1: db "Thank you ",0
fResultP2: db ".",0
fResultP3: db "After adding 5150 to your number, the answer is now: ", 0
formats: db "%s", 0
formatd: db "%d", 0
formatdlf: db "%d",10, 0 ; with line feed
SECTION .bss
name: resb 20
number: resb 4
;answer: resb 5
SECTION .text
extern printf
extern scanf
global main
main:
;;;;;;; set up stack frame
push EBP ; base pointer
mov EBP, ESP ; put stack pntr in EBP
pushad ; pushes all registers on stack
;;;;;;; ask user name
push askName ; push question
call printf ; print question
add ESP, 4 ; clean the stack (pop stack)
;;;;;;; get name input
push name
push formats ; %s (string)
call scanf
add ESP, 8 ; clean the stack (pop stack)
;;;;;;; ask user number
push askNum ; push question
call printf
add ESP, 4 ; pop stack
;;;;;;; get number input
push number
push formatd ; %d (decimal)
call scanf
add ESP, 8 ; pop stack 2X4= 8
;;;;;;; print closing sent
push fResultP1 ; "Thank you "
call printf
add ESP, 4 ; pop stack
push dword [name]
call printf
add ESP, 4 ; pop
push fResultP2 ; "."
call printf
add ESP, 4
push fResultP3 ; "After adding..."
call printf
add ESP, 4 ; pop
mov EAX, dword [number]
add EAX, 5150
push EAX ; push on the added number
push formatdlf ; has line feed
call printf
add ESP, 8 ; pop
;;;;;;; destroy stack frame ;;;;;;;;;;;;;;;;;
popad
mov ESP, EBP
pop EBP
ret
最佳答案
将push dword [name]
更改为push dword name
(或push name
)。不需要方括号。 name
是名称字符串的地址。
关于linux - nasm x86 初学者使用 C 调用 - printf scanf,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19921373/