javascript - 从 Promise.all 返回不会从包装函数返回

Question

如果 Promise.all 解析后满足某些条件，我想从函数返回。但return语句似乎没有效果，函数继续执行。

这是我的代码:

function somefunc() {

    Promise.all([match2, match3, match4, match5]).then(results => {
        console.log(results);
        if(results.indexOf(false) > -1) {
            return; // has no effect. somefunc() does NOT return. 
        }
        else {
            // ............
        };

    }).catch(err => {
      console.log(err);
    });

    // this continues to get executed even after the return staement
}

Answer 1

如果您希望返回 Promise 链中的某些内容，则必须返回 Promise.all:

function somefunc() {

    return Promise.all([match2, match3, match4, match5]).then(results => {
        console.log(results);
        if(results.indexOf(false) > -1) {
            return; // has an effect. somefunc() will return. 
        }
        else {
            // ............
        };

    }).catch(err => {
      console.log(err);
    });

    // this will not get executed after the return staement
}