javascript - Node.js应用程序中的reduce函数省略json json数据并且太麻烦

Question

我在客户变量中有这个 json:

{
    "customers": [
        {
            "id": 6,
            "name": "Joe Bloggs",
            "email": "joe@bloggs.com",
            "supplier_id": 1,
            "title": "First Supplier",
            "code": "firstsupplier"
        },
        {
            "id": 7,
            "name": "Paul",
            "email": "paul@hotmail.com",
            "supplier_id": 1,
            "title": "First Supplier",
            "code": "firstsupplier"
        },
        {
            "id": 7,
            "name": "Paul",
            "email": "paul@hotmail.com",
            "supplier_id": 3,
            "title": "New Supplier",
            "code": "new"
        },
        {
            "id": 7,
            "name": "Paul",
            "email": "paul@hotmail.com",
            "supplier_id": 4,
            "title": "PC supplier 3",
            "code": "PC03"
        },
        {
            "id": 8,
            "name": "John Doe",
            "email": "john@doe.com",
            "supplier_id": 1,
            "title": "First Supplier",
            "code": "firstsupplier"
        }
    ]
}

我想更改它，使其看起来像这样:

{
    "customers": [
        {
            "id": 6,
            "name": "Joe Bloggs",
            "email": "joe@bloggs.com",
            "suppliers": [
              {
                "supplier_id": 1,
                "title": "First Supplier",
                "code": "firstsupplier"            
              }
            ]
        },
        {
            "id": 7,
            "name": "Paul",
            "email": "paul@hotmail.com",
            "suppliers": [
              {
                "supplier_id": 1,
                "title": "First Supplier",
                "code": "firstsupplier"
              },
              {
                "supplier_id": 3,
                "title": "New Supplier",
                "code": "new"
              },
              {
                "supplier_id": 4,
                "title": "PC supplier 3",
                "code": "PC03"
              }
            ]
        },
        {
            "id": 8,
            "name": "John Doe",
            "email": "john@doe.com",
            "suppliers": [
              {
                "supplier_id": 1,
                "title": "First Supplier",
                "code": "firstsupplier"            
              }
            ]
        }
    ]
}

我已经设法让其中的一部分单独工作，但我无法让这一切在一个函数中工作。

例如我可以创建 suppliers 数组，但对于客户 ID 7 的情况，数组中仅出现一个 vendor 。

let customers = await query.offset(offset).limit(limit);

customers = customers.reduce((accumulator, item) => {
  if (accumulator[item.id]) {
    const group = accumulator[item.id];
    group.suppliers = [];
    group.suppliers.push({
      id: item.supplier_id,
      code: item.code,
      title: item.title
    });
  } else {
    accumulator[item.id] = item;
    accumulator[item.id].suppliers = [];
    accumulator[item.id].suppliers.push({
      id: item.supplier_id,
      code: item.code,
      title: item.title
    });
    delete accumulator[item.id].supplier_id;
    delete accumulator[item.id].code;
    delete accumulator[item.id].title;
  }
  return accumulator;
}, {});

我的东西看起来也很麻烦。如何在更清晰的函数中获得我想要的结果？

Answer 1

嗨@runnerpaul，在您的代码中一切都很完美，只需删除行 group.suppliers = []; 它将按照您的期望工作