MySQL选择事件前7天和事件后7天

Question

我有包含用户生日和姓名的数据库。我想选择从 7 天前到 future 7 天生日/命名日的所有用户，此选择有效，但我不知道如何解决生日/命名日为 31.12 的用户的问题。例如。 PHP 将返回“用户在 3 天前过生日”，此选择仅在年底前 7 天和新年后 7 天有效。非常感谢您的帮助。

SELECT `name`, `surname`, `gender`, ('birthday') AS event,
  DATEDIFF(NOW(), DATE(REPLACE(`birthday`, YEAR(`birthday`), YEAR(NOW())))) AS diff
FROM `users`
WHERE DATEDIFF(NOW(), DATE(REPLACE(`birthday`, YEAR(`birthday`), YEAR(NOW()))))
BETWEEN -7 AND 7
UNION
  SELECT `name`, `surname`, `gender`, ('namesday') AS event,
    DATEDIFF(NOW(), DATE(REPLACE(`namesday`, YEAR(`namesday`), YEAR(NOW())))) AS diff
  FROM `users`
  WHERE DATEDIFF(NOW(), DATE(REPLACE(`namesday`, YEAR(`namesday`), YEAR(NOW()))))
  BETWEEN -7 AND 7

Answer 1

好问题。 这是我到目前为止所做的。我不确定它是否完美，但这可能是一个好的开始。试试看吧。

select *,
if(right(birthday,5)>=right(curdate(),5),concat(year(curdate()),'-',right(birthday,5)),concat(year(curdate()+interval 1 year),'-',right(birthday,5))) as next_birthday,
if(right(birthday,5)<right(curdate(),5),concat(year(curdate()),'-',right(birthday,5)),concat(year(curdate()-interval 1 year),'-',right(birthday,5))) as prev_birthday
from users
having next_birthday 
between curdate() - interval 7 day and curdate() + interval 7 day
or prev_birthday 
between curdate() - interval 7 day and curdate()