node.js - 如何从许多相似的名称中标准化城市名称

Question

我从第 3 方 API 获取城市名称。该 API 不会返回规范化的城市名称。例如，有时是旧金山，有时是加利福尼亚州旧金山，有时是美国旧金山。我不需要街道地址等。我只需要将城市名称规范化为统一的名称。我正在寻找可以帮助我满足此要求的服务。

P.S:它不是移动应用程序，而是网络应用程序，并且位置不是来自浏览器。

Answer 1

您可以使用 Google Maps API 获取标准化地址:

1) 从以下位置获取结果:https://maps.googleapis.com/maps/api/geocode/json?address=san_francisco

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "San Francisco",
               "short_name" : "SF",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Condado San Francisco",
               "short_name" : "Condado San Francisco",
               "types" : [ "administrative_area_level_2", "political" ]
            },
            {
               "long_name" : "California",
               "short_name" : "CA",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "Estados Unidos",
               "short_name" : "US",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "San Francisco, California, EE. UU.",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : 37.9298239,
                  "lng" : -122.28178
               },
               "southwest" : {
                  "lat" : 37.6398299,
                  "lng" : -123.173825
               }
            },
            "location" : {
               "lat" : 37.7749295,
               "lng" : -122.4194155
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 37.812,
                  "lng" : -122.3482
               },
               "southwest" : {
                  "lat" : 37.70339999999999,
                  "lng" : -122.527
               }
            }
         },
         "place_id" : "ChIJIQBpAG2ahYAR_6128GcTUEo",
         "types" : [ "locality", "political" ]
      }
   ],
   "status" : "OK"
}

2) 从$data['results'][0]['address_components'][0]['long_name']中提取城市名称。

You should check that the returned content contains the described fields and the $data['status'] is "OK".

来源:https://developers.google.com/maps/documentation/geocoding/intro