我正在使用 html 和 php 制作学生注册表单。
首先,系统会要求您输入姓名、密码和电子邮件,当您单击提交时,它会将您带到另一个页面 (ChooseDepartment.php
),您可以在其中获得我的所有部门的列表数据库来选择你自己的。
现在,我完全是个新手,所以这是我在 ChooseDepartment.php 中遇到的部分 php 代码:
$ShowPossibleDep = mysql_query("SELECT NAME,DEPT_ID FROM DEPARTMENT");
if(mysql_num_rows($ShowPossibleDep) > 0){
echo "<br />"."Available departments: "." ".mysql_num_rows($ShowPossibleDep)."<br />";
echo "<br />";
echo '<form id = "dept" action = "Courses.php" method = "post">';
while($row = mysql_fetch_array($ShowPossibleDep))
{
echo $row['NAME'];
echo '<input type="radio" name="department" value=<?php $row['DEPT_ID'] ?>>';
echo "<br />";
}
echo '<input type = "submit" value = "Submit" id = "submitDepartment">';
echo </form>;
}
我试图让单选按钮的值带有
部门 ID,这样我就可以用当前为 NULL
的学生部门更新我的数据库,但我不知道如何在同一行正确使用 html 和 php!这给我语法错误!
最佳答案
因为你在 PHP
中,所以你不需要打开和关闭 PHP 标签
。
你得到语法错误的原因只是因为你没有正确操作字符串。
错误在于这一行
echo '<input type="radio" name="department" value=<?php $row['DEPT_ID'] ?>>';
^ here ^ here
所以你需要删除 PHP
标签并且需要像这样正确地连接字符串:
echo '<input type="radio" name="department" value="'.$row['DEPT_ID']. '">';
还有这个
echo </form>;
您缺少 form
标记周围的引号。应该是这样,
echo '</form>';
还有一些其他错别字,所以您的最终代码将如下所示。
$ShowPossibleDep = mysql_query("SELECT NAME,DEPT_ID FROM DEPARTMENT");
if(mysql_num_rows($ShowPossibleDep) > 0){
echo "<br />Available departments: ".mysql_num_rows($ShowPossibleDep);
//echo "<br />"; add this <br /> tag to next echo
echo '<br /><form id = "dept" action = "Courses.php" method = "post">';
while($row = mysql_fetch_array($ShowPossibleDep))
{
echo $row['NAME'];
echo '<input type="radio" name="department" value=" '.$row['DEPT_ID'].'"><br />';
//or you can do this way
//echo "<input type='radio' name='department' value='$row[DEPT_ID]'><br />";
//echo "<br />"; appended in upper statement.
}
echo '<input type = "submit" value = "Submit" id = "submitDepartment"></form>';
//echo </form>; closed already(above statement).
}
没有评论,更干净:)
$ShowPossibleDep = mysql_query("SELECT NAME,DEPT_ID FROM DEPARTMENT");
if(mysql_num_rows($ShowPossibleDep) > 0){
echo "<br />Available departments: ".mysql_num_rows($ShowPossibleDep);
echo '<br /><form id = "dept" action = "Courses.php" method = "post">';
while($row = mysql_fetch_array($ShowPossibleDep))
{
echo $row['NAME'];
echo '<input type="radio" name="department" value=" '.$row['DEPT_ID'].'"><br />';
}
echo '<input type = "submit" value = "Submit" id = "submitDepartment"></form>';
}
关于HTML 代码中的 PHP 变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33455705/