MySQL TABLE :
numbers
+----+-----+------------+
| ID | NUM | CREATED |
+----+-----+------------+
| 1 | 11 | 2018-01-01 |
+----+-----+------------+
| 2 | 22 | 2018-02-01 |
+----+-----+------------+
| 3 | 11 | 2018-03-01 |
+----+-----+------------+
| 4 | 44 | 2018-04-01 |
+----+-----+------------+
| 6 | 44 | 2018-04-02 |
+----+-----+------------+
| 5 | 22 | 2018-05-01 |
+----+-----+------------+
在此表中,ID
是主键。 NUM
是随机值,CREATED
是日期。
My Query:
SELECT
DATE_FORMAT(CREATED,'%Y-%m') AS Month,
COUNT(NUM) AS TotalNum,
COUNT(DISTINCT(NUM)) AS UniqueNum
FROM
`numbers`
GROUP BY
DATE_FORMAT(CREATED,'%Y-%m')
Result of My Query:
+---------+----------+-----------+
| Month | TotalNum | UniqueNum |
+---------+----------+-----------+
| 2018-01 | 1 | 1 |
+---------+----------+-----------+
| 2018-02 | 1 | 1 |
+---------+----------+-----------+
| 2018-03 | 1 | 1 |
+---------+----------+-----------+
| 2018-04 | 2 | 1 |
+---------+----------+-----------+
| 2018-05 | 1 | 1 |
+---------+----------+-----------+
But my Expected Result is :
+---------+----------+-----------+
| Month | TotalNum | UniqueNum |
+---------+----------+-----------+
| 2018-01 | 1 | 1 |
+---------+----------+-----------+
| 2018-02 | 1 | 1 |
+---------+----------+-----------+
| 2018-03 | 1 | 0 |
+---------+----------+-----------+
| 2018-04 | 2 | 1 |
+---------+----------+-----------+
| 2018-05 | 1 | 0 |
+---------+----------+-----------+
UniqueNum
的结果在 2018-03 月应为 0
。因为 NUM
11 已经存在于 2018-01 月。
还有
UniqueNum
的结果在 2018-05 月份应为 0
。因为 NUM
22 已经存在于 2018-02 月。
我想找到每个月的唯一编号。如何通过更新我的 MySQL 查询 获得预期结果?请帮忙。
最佳答案
您只需将表连接到自身,并只返回在之前的 CREATED 日期不存在的数字。
SELECT
DATE_FORMAT(n.CREATED,'%Y-%m') AS Month,
COUNT(n.NUM) AS TotalNum,
COUNT(un.NUM) AS UniqueNum
FROM
`numbers` n
LEFT JOIN (SELECT ID, NUM FROM numbers n1 WHERE NOT EXISTS (SELECT 1 FROM numbers n2 WHERE n1.NUM = n2.NUM AND n2.CREATED < n1.CREATED)) un ON n.ID = un.ID
GROUP BY
DATE_FORMAT(n.CREATED,'%Y-%m')
- 看到它在 sqlfiddle 中实时运行
关于mysql - 如何在 MySQL Group By 查询中查找唯一值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52147571/