我有一个像下面这样的表
CREATE TABLE Statistics(Stat_Id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
Period VARCHAR(55),
Location VARCHAR(255),
Rate_per_SqFt INT)
表格中的数据是
INSERT INTO Statistics(Period, Location, Rate_per_SqFt)
VALUES('June', 'Location A', 2500),
('June', 'Location B', 2740),
('June', 'Location C', 3200),
('July', 'Location A', 2650),
('July', 'Location B', 2800),
('July', 'Location C', 3250),
('August', 'Location A', 2750),
('August', 'Location B', 2950),
('August', 'Location C', 3230),
('October', 'Location A', 2950),
('October', 'Location B', 3950),
('October', 'Location C', 3530);
我希望特定月份的行在输出中显示为单独的列,如下所示
Period Location A Location B Location C
June 2500 2740 3200
July 2650 2800 3250
August 2750 2950 3230
October 2950 3950 3530
我如何使用查询来做到这一点
最佳答案
SELECT Period,
MAX(CASE WHEN Location = 'Location A' THEN Rate_per_SqFt ELSE NULL END) `Location A`,
MAX(CASE WHEN Location = 'Location B' THEN Rate_per_SqFt ELSE NULL END) `Location B`,
MAX(CASE WHEN Location = 'Location C' THEN Rate_per_SqFt ELSE NULL END) `Location C`
FROM statistics
GROUP BY Period
如果您有未知数量的位置,则首选动态 SQL
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'MAX(CASE WHEN Location = ''',
Location,
''' then Rate_per_SqFt ELSE NULL end) AS ',
CONCAT('`',Location,'`')
)
) INTO @sql
FROM statistics;
SET @sql = CONCAT('SELECT Period, ', @sql, '
FROM Statistics
GROUP BY Period');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
关于mysql - 将行显示为表中的列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14079560/