python - 如果列包含 NaN，如何将其转换为 int？

Question

我正在研究这个efw数据框:

2   Year    ISO_Code    Countries   INDEX   Rank    Quartile
3   2016    ALB         Albania     7.54    34      1
4   2016    DZA         Algeria     4.99    NaN     4
5   2016    AGO         Angola      5.17    155     4
6   2016    ARG         Argentina   4.84    160     NaN
7   2016    ARM         Armenia     7.57    NaN     1
8   2016    AUS         Australia   7.98    10      1
9   2016    AUT         Austria     7.58    27      NaN

假设我想转换 Rank 中的所有值和Quartile如果不是NaN，则将列转换为整数。我已经尝试过efw[["Year", "Rank", "Quartile"]].astype(int)但不断收到此错误:ValueError: cannot convert float NaN to integer

有没有办法告诉Python“跳过”NaN值，仅将其他值转换为 int ？

Answer 1

您可以将它们转换为对象

efw[["Year", "Rank", "Quartile"]].astype(object)
Out[58]: 
   Year Rank Quartile
0  2016   34        1
1  2016  NaN        4
2  2016  155        4
3  2016  160      NaN
4  2016  NaN        1
5  2016   10        1
6  2016   27      NaN

#efw[["Year", "Rank", "Quartile"]]=efw[["Year", "Rank", "Quartile"]].astype(object)