我正在尝试使用带有树莓派的 PS4 Controller 来生成输入。我已成功连接 Controller ,当我尝试运行 pygame 网站上找到的以下代码时,一切正常。
import pygame
BLACK = ( 0, 0, 0)
WHITE = ( 255, 255, 255)
class TextPrint:
def __init__(self):
self.reset()
self.font = pygame.font.Font(None, 20)
def print(self, screen, textString):
textBitmap = self.font.render(textString, True, BLACK)
screen.blit(textBitmap, [self.x, self.y])
self.y += self.line_height
def reset(self):
self.x = 10
self.y = 10
self.line_height = 15
def indent(self):
self.x += 10
def unindent(self):
self.x -= 10
pygame.init()
size = [500, 700]
screen = pygame.display.set_mode(size)
pygame.display.set_caption("My Game")
done = False
clock = pygame.time.Clock()
pygame.joystick.init()
textPrint = TextPrint()
while done==False:
for event in pygame.event.get(): # User did something
if event.type == pygame.QUIT: # If user clicked close
done=True # Flag that we are done so we exit this loop
JOYBUTTONUP JOYHATMOTION
if event.type == pygame.JOYBUTTONDOWN:
print("Joystick button pressed.")
if event.type == pygame.JOYBUTTONUP:
print("Joystick button released.")
screen.fill(WHITE)
textPrint.reset()
joystick_count = pygame.joystick.get_count()
textPrint.print(screen, "Number of joysticks: {}".format(joystick_count) )
textPrint.indent()
for i in range(joystick_count):
joystick = pygame.joystick.Joystick(i)
joystick.init()
textPrint.print(screen, "Joystick {}".format(i) )
textPrint.indent()
name = joystick.get_name()
textPrint.print(screen, "Joystick name: {}".format(name) )
axes = joystick.get_numaxes()
textPrint.print(screen, "Number of axes: {}".format(axes) )
textPrint.indent()
for i in range( axes ):
axis = joystick.get_axis( i )
textPrint.print(screen, "Axis {} value: {:>6.3f}".format(i, axis) )
textPrint.unindent()
buttons = joystick.get_numbuttons()
textPrint.print(screen, "Number of buttons: {}".format(buttons) )
textPrint.indent()
for i in range( buttons ):
button = joystick.get_button( i )
textPrint.print(screen, "Button {:>2} value: {}".format(i,button) )
textPrint.unindent()
hats = joystick.get_numhats()
textPrint.print(screen, "Number of hats: {}".format(hats) )
textPrint.indent()
for i in range( hats ):
hat = joystick.get_hat( i )
textPrint.print(screen, "Hat {} value: {}".format(i, str(hat)) )
textPrint.unindent()
textPrint.unindent()
pygame.display.flip()
clock.tick(20)
pygame.quit ()
所以,是的,当我运行上面的代码时,一切正常,但是我根本不想生成游戏,我只对从方向键或帽子获取输入感兴趣。为了做到这一点,我根据上面的代码编写了自己的代码
import pygame
pygame.joystick.init()
while True:
joystick = pygame.joystick.Joystick(0)
joystick.init()
hat = joystick.get_hat(0)
print(str(hat))
当我运行上面的代码时,它会运行并且没有语法错误,但是无论我按下方向键的哪个按钮,它都会连续打印(0,0)。 Controller 仍然处于连接状态,这表明由于某种原因我的新代码没有接收输入。
感谢您花时间阅读这篇长文,我们将不胜感激。
亲切的问候
最佳答案
您必须调用 pygame.event
之一定期运行(例如 pygame.event.pump
或 for event in pygame.event.get():
),其他函数如 Joystick.get_hat
> 和 pygame.mouse.get_pressed
将不起作用,并且 pygame 窗口将在一段时间后变得无响应。
您也不需要每帧创建并初始化一个新的操纵杆对象。在 while
循环之前执行一次。这是一个最小的完整示例:
import pygame as pg
pg.init()
screen = pg.display.set_mode((100, 100))
clock = pg.time.Clock()
# Create a list of available joysticks and initialize them.
joysticks = [pg.joystick.Joystick(x) for x in range(pg.joystick.get_count())]
for joystick in joysticks:
joystick.init()
running = True
while running:
for event in pg.event.get():
if event.type == pg.QUIT:
running = False
elif event.type == pg.JOYBUTTONDOWN:
if event.button == 6: # Back button.
running = False
for joystick in joysticks: # Iterate over the available joysticks.
if joystick.get_id() == 0: # The first joystick.
numhats = joystick.get_numhats()
for hat in range(numhats): # Check all hats of the joystick.
print(joystick.get_hat(hat))
screen.fill((30, 30, 50))
pg.display.flip()
clock.tick(60)
pg.quit()
关于python - 编辑后的操纵杆代码未接收输入,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53106850/