我正在尝试提取与特定代码相关的特定数据。我设法将数据提取到新的字典列表中,但我需要将日期格式从“Y-m-d H:M:S”更改为“d/m/Y”。
data = [
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.32'},
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.16'},
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.18'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.43'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.33'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.01'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.53'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.22'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.12'},
]
specific_code_data= []
def find_result_with_specific_code(x):
global specific_code_data
for d in test_data.ilab_data:
if d['code'] == x:
specific_code_data.append(d)
return specific_code_data
我尝试写一些类似的内容:
for d in specific_code_data:
indate = d['collection_date_time']
dt_obj = datetime.datetime.strptime(indate, '%Y-%m-%d %H:%M:%S')
dt_str = datetime.datetime.strftime(dt_obj, '%d/%m/%Y')
但我不确定如何将字典列表中的键 collection_date_time 的值更改为我需要的格式。任何帮助或指出正确的方向将不胜感激。
最佳答案
'but I need to changed the date format from 'Y-m-d H:M:S' to 'd/m/Y'
我也会跳到这里...使用pandas
data = [
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.32'},
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.16'},
{'collection_date_time': '2018-05-01 00:00:00', 'code': '96423', 'result': '0.18'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.43'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.33'},
{'collection_date_time': '2017-12-24 13:04:00', 'code': '45674', 'result': '0.01'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.53'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.22'},
{'collection_date_time': '2018-04-08 09:43:00', 'code': '12343', 'result': '0.12'},
]
sample = pd.DataFrame([d for d in data])
sample['collection_date_time'] = pd.to_datetime(sample['collection_date_time']).dt.normalize()
sample['collection_date_time'] = sample['collection_date_time'].dt.strftime("%d/%m/%Y")
data = []
for value in sample.values:
list_of_dict = {}
list_of_dict['code'] = value[0]
list_of_dict['collection_date_time'] = value[1]
list_of_dict['result'] = value[2]
data.append(list_of_dict)
print(data)
[{'code': '96423', 'collection_date_time': '01/05/2018', 'result': '0.32'},
{'code': '96423', 'collection_date_time': '01/05/2018', 'result': '0.16'},
{'code': '96423', 'collection_date_time': '01/05/2018', 'result': '0.18'},
{'code': '45674', 'collection_date_time': '24/12/2017', 'result': '0.43'},
{'code': '45674', 'collection_date_time': '24/12/2017', 'result': '0.33'},
{'code': '45674', 'collection_date_time': '24/12/2017', 'result': '0.01'},
{'code': '12343', 'collection_date_time': '08/04/2018', 'result': '0.53'},
{'code': '12343', 'collection_date_time': '08/04/2018', 'result': '0.22'},
{'code': '12343', 'collection_date_time': '08/04/2018', 'result': '0.12'}]
关于python - 更改字典列表中的相同值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53322571/