我有这个问题,我想解决。我需要使用前向映射剪切图像,然后使用后向映射将其剪切回来。如果我删除 backMapping 但不添加它,则该代码有效。这是我的代码,感谢任何帮助!
import cv2
import numpy as np
img = cv2. imread("Lena2.jpg")
rows, cols, c = img.shape
Bx = 0.2
By = 0.3
def forMap (img,Bx,By):
rows = img.shape[0]
cols = img.shape[1]
imgForward = np.ndarray(shape = (int(cols + rows*By), int(rows + cols*Bx),3))
for row in range(rows):
for col in range(cols):
np.matmul(imgForward,np.array([[rows],[cols]]))
imgForward[int (row+col*By), int(col+row*Bx)] = img[row,col]/255
return imgForward
def backMap (img, Bx, By):
n = int(1/(1-Bx*By))
rows = img.shape[0]
cols = img.shape[1]
imgBackwards = np.ndarray(shape = img.shape);
for row in range(rows):
for col in range(cols):
backCol = int (n*(col+row*Bx))
backRow = int (n*(col+row*By))
np.matmul(imgBackwards,np.array([[rows],[cols]]))
imgBackwards[int(backRow+backCol*By), int(backCol + backRow*Bx)] = img[row,col]
forMap(img, Bx, By)
BackMapping = (backMap(img, Bx, By))
cv2.imshow("original image", img)
cv2.imshow("Forward Mapping", forMap)
cv2.imshow("Backward mapping", backMap)
cv2.waitKey(0)
最佳答案
正向映射:
形状的顺序应该是(行数,列数, channel 数)
,所以它变成
imgForward = np.ndarray(shape=(int(rows + cols*Bx),int(cols + rows*By),3))
不需要这一行np.matmul(imgForward,np.array([[rows],[cols]]))
然后,您必须将所有 3 个 channel 复制到新位置
imgForward[int(row+col*Bx), int(col+row*By),:] = img[row,col,:]
向后映射
只需将 int(row+col*Bx), int(col+row*By)
更改为 int(row-col*Bx), int(col-row *作者)
所以你的代码变成了
import cv2
import numpy as np
img = cv2. imread('one.jpg')
rows, cols, c = img.shape
Bx = 0.2
By = 0.3
def forMap (img,Bx,By):
rows = img.shape[0]
cols = img.shape[1]
imgForward = np.zeros((int(rows + cols*Bx),int(cols + rows*By),3), dtype=np.ubyte)
for row in range(rows):
for col in range(cols):
#np.matmul(imgForward,np.array([[rows],[cols]]))
imgForward[int(row+col*Bx), int(col+row*By),:] = img[row,col,:]
return imgForward
def backMap (img, Bx, By):
rows = img.shape[0]
cols = img.shape[1]
imgBackwards = np.zeros(shape=img.shape, dtype=np.ubyte);
for row in range(rows):
for col in range(cols):
backCol = int (col-row*By)
backRow = int (row-col*Bx)
#np.matmul(imgBackwards,np.array([[rows],[cols],3]))
imgBackwards[backRow, backCol, :] = img[row,col,:]
return imgBackwards
fimg = forMap(img, Bx, By)
bimg = backMap(fimg, Bx, By)
cv2.imshow("original image", img)
cv2.imshow("Forward Mapping", fimg)
cv2.imshow("Backward mapping", bimg)
cv2.waitKey(0)
cv2.destroyAllWindows()
关于python - 使用 Bx 和 By 在 python 中剪切图像以进行前向和后向映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53414696/