python - 类型错误:promovePeao() 缺少 1 个必需的位置参数: 'player'

Question

我有以下代码:

if(promovePeao(board,player) or (not getMovesPecas(board)['W'])):
   print("HELLO")

我的目的是检查棋盘最后一排是否有玩家

def promovePeao(self, board, player):
    if(player == 'B'):
        for a in (1,9):
            if(board[(1,a)] == player):
                return True
        return False
    else:
        for b in (1,9):
            if(board[(8,b)] == player):
                return True
        return False

但是当我执行代码时，我收到错误:

TypeError: promovePeao() missing 1 required positional argument: 'player'

有什么想法吗？

Answer 1

您像方法一样定义promovePeao，但像函数一样调用它。您收到错误是因为该函数需要 self 参数，但它不会自动传递，因为它没有在对象上调用。将其更改为:

def promovePeao(board, player): #Note that there is no self argument
    if(player == 'B'):
        for a in (1,9):
            if(board[(1,a)] == player):
                return True
        return False
    else:
        for b in (1,9):
            if(board[(8,b)] == player):
                return True
        return False