Python 3.x _tkinter.TclError : bad window path name ".!toplevel"

Question

我想在 tkinter 中做一个弹出窗口小部件，用户可以在其中输入一些数据。但是在测试时我遇到了以下错误:

  File "returnWeeksGUI_v1.py", line 363, in __init__
    self.content = program.popup("Add_label")
  File "returnWeeksGUI_v1.py", line 296, in popup
    self.w=popupWindow(self.master,popup_type)
  File "returnWeeksGUI_v1.py", line 42, in __init__
    self.bu=tk.Button(top,text='Ok',command=self.cleanup(win_type))
  File "C:\Users\Fernanda\AppData\Local\Programs\Python\Python37-32\lib\tkinter\__init__.py", line 2369, in __init__
    Widget.__init__(self, master, 'button', cnf, kw)
  File "C:\Users\Fernanda\AppData\Local\Programs\Python\Python37-32\lib\tkinter\__init__.py", line 2299, in __init__
    (widgetName, self._w) + extra + self._options(cnf))
_tkinter.TclError: bad window path name ".!toplevel"

已经调试和编辑了3天的代码，但仍然没有找到合适的解决方案。

<小时/>

代码

我有一些导入和变量:

import tkinter as tk

models = {
    "text":["TXT",50,50],
    "DD":["DD",50,50],
    "MM":["MM",50,50],
    "AA":["AA",50,50],
    "MC":["MC",50,50],
    "DP":["DP",50,50],  
    }

我有一个 tkinter 类(class):

class App(tk.Frame):
    def __init__(self,master=None):
        super().__init__(master)
        self.master = master

        #This class has some variables:
        self.pu= program.popup("Add_label")

    def popup(self,popup_type):
            self.w=popupWindow(self.master,popup_type)
            self.master.wait_window(self.w.top)

我还有一个从 a question in StackOverflow 获取的弹出代码，我根据自己的目的进行了修改。它显示了用户必须完成/选择的一些单选按钮/条目。

class popupWindow(object):
    def __init__(self,master,win_type):
        top=self.top=tk.Toplevel(master)
        if str(win_type) == "Add_label":
            """
            Here goes a large piece of code that is irrelevant.  
            """
            # Until I have this set of statements which break the program.
            self.bu=tk.Button(top,text='Ok',command=self.cleanup(win_type))
            self.bu.pack()

        elif str(win_type) == "Add_box":
            #...
            self.bu=tk.Button(top,text='Ok',command=self.cleanup(win_type))
            self.bu.pack()

        elif str(win_type) == "Delete_label":
            #...
            self.bu=tk.Button(top,text='Ok',command=self.cleanup(win_type))
            self.bu.pack()

        elif str(win_type) == "Delete_box": 
            #...
            self.bu=tk.Button(top,text='Ok',command=self.cleanup(win_type))
            self.bu.pack()

    def cleanup(self,win_type):
        #...
        # At the end, a destroy method is called.
        self.top.destroy()

实例是这样的:

root = tk.Tk()
program = App(root)
program.mainloop()

弹出窗口不是由 __init__() 函数中的变量触发的。事实上，当按下某个按钮时它就会出现。不过，我在这里用一个变量代替了它，因为这样会更容易分析。触发弹出窗口的按钮很好。我之前查过。

<小时/>

如果有人能提供帮助，我将不胜感激。谢谢。

Answer 1

您现在正在创建按钮期间调用 self.cleanup(win_type) ，从而破坏了您尝试添加按钮的窗口。一种解决方案是将其编写为 command=lambda: self.cleanup(win_type)，以便将调用推迟到实际单击按钮为止。 – Jasonharper 的评论回答