python - 确定网站是否是网上商店

Question

我正在尝试确定网站列表中的网站是否为网上商店。

似乎大多数网络商店都有:

• a 标签的 href 中包含“cart”一词
• 分配给类名称中包含“cart”一词的 li 标记

我相信我必须利用正则表达式，然后告诉 BeautifulSoup find 方法在 a 或 中搜索此正则表达式的 HTML 数据>li 标签。我该怎么办？

到目前为止，下面的代码在 HTML 数据中搜索 a 标记，其中 href 为 EXACTLY cart。

代码

import re
from bs4 import BeautifulSoup
from selenium import webdriver

websites = [
    'https://www.nike.com/',
    'https://www.youtube.com/',
    'https://www.google.com/',
    'https://www.amazon.com/',
    'https://www.gamestop.com/'
]
shops = []

driver = webdriver.Chrome('chromedriver')
options = webdriver.ChromeOptions()
options.headless = True
options.add_argument('log-level=3')

with webdriver.Chrome(options=options) as driver:
    for url in websites:
        driver.get(url)
        cart = re.compile('.*cart.*', re.IGNORECASE)
        soup = BeautifulSoup(driver.page_source, 'html.parser')
        if soup.find('a', href=cart):
            shops.append(url)

print('\nSHOPS FOUND:')
for shop in shops:
    print(shop)

输出:

SHOPS FOUND:
https://www.nike.com/
https://www.amazon.com/

Answer 1

您可以将 contains * 运算符与 css 属性选择器一起使用来指定 class 属性或 href 属性包含子字符串 cart。使用 Or 语法将两者(class 和 href)结合起来。 TODO:您可以考虑添加等待条件以确保所有 li 和 a 标记元素首先出现。

from bs4 import BeautifulSoup
from selenium import webdriver

websites = [
    'https://www.nike.com/',
    'https://www.youtube.com/',
    'https://www.google.com/',
    'https://www.amazon.com/',
    'https://www.gamestop.com/'
]
shops = []

driver = webdriver.Chrome('chromedriver')
options = webdriver.ChromeOptions()
options.headless = True
options.add_argument('log-level=3')

with webdriver.Chrome(options=options) as driver:
    for url in websites:
        driver.get(url)
        soup = BeautifulSoup(driver.page_source, 'html.parser')
        items = soup.select('a[href*=cart], li[class*=cart]')
        if len(items) > 0:
                shops.append(url)
print('\nSHOPS FOUND:')
for shop in shops:
    print(shop)