python - 如何使用 python 与 exe 文件交互

Question

我有一个 exe 文件，它接受来自键盘的输入，并根据输入文本返回响应。当尝试读取 exe 返回的输出时，Python 脚本卡住。

我运行的是 Windows 7 和 python3.7。我已经尝试过continuously interacting with .exe file using python的答案.

from subprocess import Popen, PIPE

location = "C:\\Users\\file.exe"

p= Popen([location],stdin=PIPE,stdout=PIPE,stderr=PIPE, encoding="UTF8")
command='START'
p.stdin.write(command)
response=p.stdout.read()

我希望用输出文本填充响应，但程序却卡住在该行。

我想要交互的exe文件是here (胚胎文件)

Answer 1

调用p.stdout.readline()而不是p.stdout.read()。这将一次给您一行，而不是等待进程关闭其标准输出管道。欲了解更多信息，请阅读documentation .

这是一个更详细的示例。想象一下这个脚本是您的 exe 文件的替代品:

# scratch.py
from time import sleep

for i in range(10):
    print('This is line', i)
    sleep(1)

现在我启动该脚本，并尝试读取其输出:

from subprocess import Popen, PIPE, STDOUT

p = Popen(['python', 'scratch.py'], stdin=PIPE, stdout=PIPE, stderr=STDOUT, encoding='UTF8')
for i in range(10):
    response = p.stdout.read()
    print('Response', i)
    print(response)

结果如下所示:它等待十秒钟，然后打印出以下内容:

Response 0
This is line 0
This is line 1
This is line 2
This is line 3
This is line 4
This is line 5
This is line 6
This is line 7
This is line 8
This is line 9

Response 1

Response 2

Response 3

Response 4

Response 5

Response 6

Response 7

Response 8

Response 9

现在，如果我将其更改为 readline()，我会得到:

Response 0
This is line 0

Response 1
This is line 1

Response 2
This is line 2

Response 3
This is line 3

Response 4
This is line 4

Response 5
This is line 5

Response 6
This is line 6

Response 7
This is line 7

Response 8
This is line 8

Response 9
This is line 9