参数
num_dict: dictionary
all values are numeric
min_cutoff: float
与 num_dict 值进行比较。返回其值 >= min_cutoff 的所有键。
我的字典是{'Denver': 200, 'Houston': 100, 'NOLA':50}
def keys_get_cutoff(num_dict, min_cutoff):
for k, v in num_dict.items():
if v >= min_cutoff:
print(keys_get_cutoff(num_dict, min_cutoff))
最佳答案
def keys_get_cutoff(dict, min_value):
return [key for key in dict.keys() if dict[key] >= min_value]
关于python - 返回 num_dict 中值大于或等于 min_cutoff 的所有键(按设置)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/57103239/