java - mySQL 到 PHP 到 JSON : String Cannot be Converted to JSONObject

标签 java php mysql json

我正在尝试使用 PHP 从 mySQL 数据库中获取数据。这是我第一次真正尝试远程获取数据并使用 JSON。 php 文件运行正常,因为它在浏览器中输出为 JSON 字符串,我使用 JSONLint 对其进行了验证。 .所以,我不确定我在这里做错了什么。任何帮助将不胜感激

这是 LogCat 抛出的内容:

Error parsing data org.json.JSONException: Value <?xml of type java.lang.String cannot be converted to JSONObject
threadid=9: thread exiting with uncaught exception (group=0x401dce20)
FATAL EXCEPTION: Thread-10
java.lang.NullPointerException
at com.andaero.test.JSON.JSONMain$1.run(JSONMain.java:39)
at java.lang.Thread.run(Thread.java:1020)

更新: 我按照 Mark 的要求从 php 文件中删除了 echo 方法。我认为这与“JSONArray a = json.getJSONArray("regulatory")”有关。我也尝试了其他人的方法,但没有成功。

这里是类:

public class JSONfunctions {

    public static JSONObject getJSONfromURL(String url) {
        InputStream is = null;
        String result = "regulatory";
        JSONObject jArray = null;

        // http post
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        // convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        try {

            jArray = new JSONObject(result);
        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }

        return jArray;
    }
}

列表 Activity :

public class JSONMain extends ListActivity {
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.listview);

        final ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();

        new Thread(new Runnable() {
            public void run() {
                JSONObject json = JSONfunctions
                        .getJSONfromURL("http://192.168.1.34/andaero/regulatory_list_ASC.php");

                try {

                    JSONArray a = json.getJSONArray("regulatory");

                    for (int i = 0; i < a.length(); i++) {
                        HashMap<String, String> map = new HashMap<String, String>();
                        JSONObject e = a.getJSONObject(i);

                        map.put("id", String.valueOf(i));
                        map.put("label", e.getString("label"));
                        map.put("title", e.getString("title"));
                        map.put("caption", e.getString("description"));
                        map.put("dummy", e.getString("gotoURL"));
                        mylist.add(map);
                    }
                } catch (JSONException e) {
                    Log.e("log_tag", "Error parsing data " + e.toString());
                }
            }
        }).start();

        ListAdapter adapter = new SimpleAdapter(this, mylist,
                R.layout.list_item, new String[] { "label", "title", "caption",
                        "dummy" }, new int[] { R.id.label, R.id.listTitle,
                        R.id.caption, R.id.dummy });

        setListAdapter(adapter);

        final ListView lv = getListView();
        lv.setTextFilterEnabled(true);
        lv.setOnItemClickListener(new OnItemClickListener() {
            public void onItemClick(AdapterView<?> parent, View view,
                    int position, long id) {
                @SuppressWarnings("unchecked")
                HashMap<String, String> o = (HashMap<String, String>) lv
                        .getItemAtPosition(position);
                Toast.makeText(JSONMain.this,
                        "ID '" + o.get("id") + "' was clicked.",
                        Toast.LENGTH_SHORT).show();

            }
        });
    }
} 

PHP:

<?php
//MySQL Database Connect
include 'andaerologin.php';

mysql_select_db("andaero");
$sql=mysql_query("select * from regulatory_list");

$output = array();
while($row = mysql_fetch_assoc($sql)) {
    $output['regulatory'][] = $row;
}

exit (json_encode($output));

mysql_close();
?>

最佳答案

尝试将您的 PHP 更改为:

$output = new stdClass();
$output->regulatory = array();
while($row = mysql_fetch_assoc($sql)) {
    $output->regulatory[] = $row;
}

header('Content-type: application/json');
echo (json_encode($output));

关于java - mySQL 到 PHP 到 JSON : String Cannot be Converted to JSONObject,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8934412/

相关文章:

java - IntelliJ IDEA 中公共(public) setter/mutator 方法的 "Access can be private"警告消息

java - 理解java的同步集合

php - 获取百分号前的数字

php - 使用 mysqli 从数据库中选择、分组和求和结果

java - @PicketLink 注释类未在 identity.login() 中使用

php - 存储过程和 PHP 表单

php - 用 PHP 解析 XML?

php 错误 - 额外循环运行一次?

php - 在 php 中创建的数据源未验证

java - java中的实数或值是什么意思以及java中原始类型的非常基本的解释