python - 程序输出错误的输出

Question

我正在为一个学校项目执行此操作，并且需要知道为什么即使条件不满足，输出仍然会显示“爱沙尼亚”。另外，为什么程序在某些地方放置“无”？ 我不确定是否应该包含所有代码或仅包含一部分，因此我将把整个代码都包含在内，以防万一。我是新人，所以请原谅我的独裁......

# Purpose: Create a program that suggests a vacation spot based on user input


# Here is the Input, or answers to the questions
print('Hello! This is your Dream Vacation Spot!')
answers = [input('Do you want a "hot" or "cold" place? '),
        input('Do you want a place that has a "huge" pop or "small" pop? '),
        input('Are you planning on getting wet? "y" or "n": ')]

# Create the intro that displays what they said. 
def intro():
    for i in range(2):
        print('')
    print('Hi! Welcome to your Dream Vacation Spot!')
    print('')
    print('Listed here, are your answers:')
    print('Hot or cold place? You said ' + answers[0])
    print('Huge population, or small towny place? You said ' + answers[1])
    print('Want to get wet? You said ' + answers[2])
    for i in range(2):
        print('')

# Start using the if/ elif statements to decide places to go.
def main():
    if answers[0] == 'cold' and answers[1] == 'small' and answers[2] == 'wet' or 'Wet':
        one = 'Congrats!! You got... \n Estonia!'
        print(one)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'big' or 'Big' and answers[2] == 'y' or 'Y':
        two = 'Congrats!! You got... \n Geirangerfjord, Norway!'
        print(two)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        three = 'Congrats!! You got... \n Innsbruck, Austria!'
        print(three)

    elif answers[0] == 'cold' or 'Cold' and answers[1] == 'big' or 'Big' and answers[2] == 'n' or 'N':
        four = 'Congrats!! You got... \n Yellowknife, Canada!'
        print(four)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'big' or 'Big' and answers[2] == 'n' or 'N':
        five = 'Congrats!! You got... \n Austin, Texas!'
        print(five)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        six = 'Congrats!! You got... \n Bisbee, Arizona!'
        print(six)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'n' or 'N':
        seven = 'Congrats!! You got... \n Grand Junction, Colorado!'
        print(seven)

    elif answers[0] == 'hot' or 'Hot' and answers[1] == 'small' or 'Small' and answers[2] == 'y' or 'Y':
        eight = 'Congrats!! You got... \n Muskogee, Oklahoma!'
        print(eight)



def printAll():
    print(intro())
    print(main())
    for i in range(2):
        print('')
    print('Have a nice trip!!!')

printAll()

Answer 1

唷!这是很多代码，并且可能有一些关于如何处理复杂逻辑的重要教训，让我们看看我们是否不能让它工作得更好一点。

首先，我建议您使用列表理解和 lower() 函数来简化答案中的可能性数量

answers_lowercase = [x.lower() for x in answers]

那么为什么不在 if/elif 语句中使用单个逻辑测试，例如

def main():
    if answers_lowercase == ['cold', 'small', 'wet'] :
        print('Congrats!! You got... \n Estonia!')

可能还有更简洁、Python 的方式来编写代码:即从表中查找正确答案，而不是使用六个“if”语句，以及如果用户在输入中输入错误时进行错误处理。好的东西值得研究和学习。祝你好运!