python - 通过域名将网络流量与授权列表进行比较

Question

我正在尝试解析网络流量并将流量中的域名与最常见网站的列表进行比较。目的是打印不在常见网站列表中的所有网站名称

with open('/Users/downloads/scripting_for_security/resources/top_100.txt') as f:
    safeAdd = f.readlines(),


with open('/Users/downloads/scripting_for_security/resources/traffic_log.txt') as n:
    netTraffic = n.readlines(),

domainTraffic = re.findall(r'\s(?:www.)?(\w+.com)', netTraffic)


for i in safeAdd:
    for e in domainTraffic:
        if i != e:
            print(e)

出现类型错误

TypeError Traceback (most recent call last) in 8 netTraffic = n.readlines(), 9 ---> 10 domainTraffic = re.findall(r'\s(?:www.)?(\w+.com)', netTraffic) 11 12

~/anaconda3/lib/python3.7/re.py in findall(pattern, string, flags) 221 222 Empty matches are included in the result.""" --> 223 return _compile(pattern, flags).findall(string) 224 225 def finditer(pattern, string, flags=0):

TypeError: expected string or bytes-like object

Answer 1

netTraffic 是一个列表，按照https://docs.python.org/3/tutorial/inputoutput.html

findall 需要字符串类型的第二个参数 https://docs.python.org/3/library/re.html#re.findall