这些天我正在努力根据两个不同的图形的共同节点来映射它们。这是两个图表的样子。节点的颜色表示蓝色节点为优先级1，黄色节点为优先级2。
共享同一个节点的节点，我想将它们组合起来。这就是我想要实现的目标。在这种情况下，10和190分别是31、130、204和240的公共(public)节点。
这是我尝试过的代码。
for node1, node2 in Graph2.edges():
if Graph1.has_edge(node1, node2):
for attr in Graph2.adj[node1][node2]:
if (Graph1.node[node1]['priority']==1):
name = str(node1) + '/' + str(node2)
mapping = {n1: name, node2: name}
Graph2 =nx.relabel_nodes(Graph2, mapping)
pos1 = nx.shell_layout(Graph2)
nodes = nx.draw_networkx_nodes(Graph2, pos1, node_size=2000, node_color = 'b' , alpha=0.3, with_labels = True)
nx.draw_networkx_edges(Graph2, pos1, width=1.5, alpha=0.3, edge_color='k')
nx.draw_networkx_labels(Graph2, pos1, font_size=15, font_family='sans-serif')
有人可以帮我实现这个目标吗？
非常感谢!!
最佳答案
对于那些正在寻找类似解决方案的人，我尝试解决优先级 1 的上述问题，这意味着蓝色节点。对于其余的优先事项也执行同样的操作。这里的优先级和名称是我的图形属性。
try:
for n1, n2, attr in list(graph1.edges(data ='True')):
for x1, x2, attr1 in list(graph2.edges(data ='True')):
if ((graph1.node[n1]['priority'] ==1) & (graph1.node[n1]['name'] =='Start')):
if ((graph2.node[x1]['priority'] ==1) & (graph2.node[x1]['name'] =='Start')):
name1 = str(n1) + '/' + str(x1)
mapping1 = {n1: name1, x1:name1}
graph1 =nx.relabel_nodes(graph1, mapping1)
graph2 =nx.relabel_nodes(graph2, mapping1)
except KeyError:
print('')
try:
for n1, n2, attr in list(graph1.edges(data ='True')):
for x1, x2, attr1 in list(graph2.edges(data ='True')):
if ((graph1.node[n2]['priority'] ==1) & (graph1.node[n2]['name'] =='End')):
if ((graph2.node[x2]['priority'] ==1) & (graph2.node[x2]['name'] =='End')):
name1 = str(n2) + '/' + str(x2)
mapping1 = {n2: name1, x2:name1}
graph1 =nx.relabel_nodes(graph1, mapping1)
graph2 =nx.relabel_nodes(graph2, mapping1)
except KeyError:
print('')
关于python - 在 Networkx 中映射两个图，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58534054/