我有以下查询:
SELECT SUM( cost )
FROM (
SELECT s.cost
FROM sandwiches AS s
WHERE s.name = "Cheese Steak"
)
UNION (
SELECT p.cost
FROM pizza AS p
WHERE TYPE = "Plain"
AND SIZE = "L"
)
这给了我一个错误:
#1248 - Every derived table must have its own alias
最佳答案
你需要给你的临时表起别名
SELECT SUM( cost )
FROM
(
(
SELECT s.cost
FROM sandwiches AS s
WHERE s.name = "Cheese Steak"
) AS T1
UNION
(
SELECT p.cost
FROM pizza AS p
WHERE TYPE = "Plain"
AND SIZE = "L"
) AS T2
) AS T
关于mysql - 每个派生表都必须在 MySQL 中有自己的别名错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5824873/